SOLUTION: CAN SOMEONE PLEASE HELP ME WITH THIS PROBLEM: R(x)= x^3 - 2x^2 - 7 / x^6 - 2x^5 + 6x^2 - 4. How many vertical asymptotes are possible?

Algebra ->  Polynomials-and-rational-expressions -> SOLUTION: CAN SOMEONE PLEASE HELP ME WITH THIS PROBLEM: R(x)= x^3 - 2x^2 - 7 / x^6 - 2x^5 + 6x^2 - 4. How many vertical asymptotes are possible?      Log On


   

Question 157933: CAN SOMEONE PLEASE HELP ME WITH THIS PROBLEM:
R(x)= x^3 - 2x^2 - 7 / x^6 - 2x^5 + 6x^2 - 4. How many vertical asymptotes are possible?
Answer by jim_thompson5910(35256) About Me  (Show Source):
You can put this solution on YOUR website!
Notice how the degree of the denominator is 6. So this means that there are a max of 6 real zeros possible for x%5E6+-+2x%5E5+%2B+6x%5E2+-+4. So this means that there are a max of 6 vertical asymptotes possible (since each zero of a denominator results in division by zero).