SOLUTION: CAN SOMEONE PLEASE HELP ME WITH THIS PROBLEM: Consider d(x)=(x+2)^3+3; what is the new equation for d(x) if it is 4 times larger? a. d(x)=4(x+2)^3 +12 b. d(x)=(x+2)^12 + 3 c.

Algebra ->  Polynomials-and-rational-expressions -> SOLUTION: CAN SOMEONE PLEASE HELP ME WITH THIS PROBLEM: Consider d(x)=(x+2)^3+3; what is the new equation for d(x) if it is 4 times larger? a. d(x)=4(x+2)^3 +12 b. d(x)=(x+2)^12 + 3 c.      Log On


   

Question 157916: CAN SOMEONE PLEASE HELP ME WITH THIS PROBLEM:
Consider d(x)=(x+2)^3+3; what is the new equation for d(x) if it is 4 times larger?
a. d(x)=4(x+2)^3 +12
b. d(x)=(x+2)^12 + 3
c. d(x)= 4(x+2)^3
d. d(x)=4(x+2)^3 +3
Answer by jim_thompson5910(35256) About Me  (Show Source):
You can put this solution on YOUR website!
+d%28x%29=%28x%2B2%29%5E3%2B3 Start with the given function


4%2Ad%28x%29=4%28%28x%2B2%29%5E3+%2B3%29 Multiply both sides by 4 (since we're looking for the function that is "4 times larger")


4%2Ad%28x%29=4%28x%2B2%29%5E3+%2B4%283%29 Distribute


4%2Ad%28x%29=4%28x%2B2%29%5E3+%2B12 Multiply


So the new function for d(x) that is 4 times larger is a) d%28x%29=4%28x%2B2%29%5E3+%2B12