Question 149806This question is from textbook
: Find the product of (2x2 + 7x - 4) with the quotient of (36x5 + 9x4 + 18x3) ÷ 3x3.
How i would go back about setting the problem up? Please don't give me the answer. I just want to understand how to set the problem up. Thank you
This question is from textbook
Answer by nerdybill(7384)   (Show Source):
You can put this solution on YOUR website! Think of it this way, there are two parts:
Part 1: "product" (multiplication)
Part 2: "quotient" (division)
.
Concentrate on Part 2 FIRST!
(36x^5 + 9x^4 + 18x^3) ÷ 3x^3
We can "distribute" the division to EACH term inside the parenthesis:
= (36x^5 ÷ 3x^3) + (9x^4 ÷ 3x^3) + (18x^3 ÷ 3x^3)
Now, looking at just the numbers, we can reduce thus:
= (13x^5 ÷ x^3) + (3x^4 ÷ x^3) + (6x^3 ÷ x^3)
Now, looking at the x's, we can reduce thus:
= (13x^2) + (3x) + (6)
Resulting in:
= 13x^2 + 3x + 6
.
Finally, we do Part 1:
(2x^2 + 7x - 4)(13x^2 + 3x + 6)
Multiply each term inside the first parenthesis with each term in the second:
= (26x^4 + 6x^3 + 12x^2) + (91x^3 + 21x^2 - 24) + (-52x^2 - 12x - 24)
Now, group like-terms:
= 26x^4 + (6x^3 + 91x^3) + (12x^2 + 21x^2 - 52x^2) + (- 24- 24)
= 26x^4 + (97x^3) + (-19x^2) + (-48)
= 26x^4 + 97x^3 - 19x^2 - 48
|
|
|
