SOLUTION: solve. x^2-x-6>0 I could use anyones help on this question. Thanks.

Algebra ->  Polynomials-and-rational-expressions -> SOLUTION: solve. x^2-x-6>0 I could use anyones help on this question. Thanks.      Log On


   

Question 149263This question is from textbook
: solve.
x^2-x-6>0
I could use anyones help on this question. Thanks. This question is from textbook

Answer by josmiceli(19441) About Me  (Show Source):
You can put this solution on YOUR website!
x%5E2+-+x+-+6 is easily factored to
%28x+%2B+2%29%28x+-+3%29
In order for x%5E2+-+x+-+6+%3E+0 to be true, either both of the factors
must be (+) or they both must be (-)
------------------
If both factors are to be (+), then x+%3E+3
If both factors are to be (-), then x+%3C+-2
------------------
So, this works out to be
3+%3C+x+%3C+-2
In other words, x can't be any value between -2 and +3, including
-2 and +3