SOLUTION: Factor completely x^10y^3 – 4x^9y^2 – 21x^8y

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Question 146160: Factor completely



x^10y^3 – 4x^9y^2 – 21x^8y

Answer by jim_thompson5910(35256) About Me  (Show Source):
You can put this solution on YOUR website!

x%5E10y%5E3-4x%5E9y%5E2-21x%5E8y Start with the given expression


x%5E8y%28x%5E2y%5E2-4xy-21%29 Factor out the GCF x%5E8y


Now let's focus on the inner expression x%5E2y%5E2-4xy-21




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Looking at 1x%5E2y%5E2-4xy-21 we can see that the first term is 1x%5E2y%5E2 and the last term is -21 where the coefficients are 1 and -21 respectively.

Now multiply the first coefficient 1 and the last coefficient -21 to get -21. Now what two numbers multiply to -21 and add to the middle coefficient -4? Let's list all of the factors of -21:



Factors of -21:
1,3,7,21

-1,-3,-7,-21 ...List the negative factors as well. This will allow us to find all possible combinations

These factors pair up and multiply to -21
(1)*(-21)
(3)*(-7)
(-1)*(21)
(-3)*(7)

note: remember, the product of a negative and a positive number is a negative number


Now which of these pairs add to -4? Lets make a table of all of the pairs of factors we multiplied and see which two numbers add to -4

First NumberSecond NumberSum
1-211+(-21)=-20
3-73+(-7)=-4
-121-1+21=20
-37-3+7=4



From this list we can see that 3 and -7 add up to -4 and multiply to -21


Now looking at the expression 1x%5E2y%5E2-4xy-21, replace -4xy with 3xy%2B-7xy (notice 3xy%2B-7xy adds up to -4xy. So it is equivalent to -4xy)

1x%5E2y%5E2%2Bhighlight%283xy%2B-7xy%29%2B-21


Now let's factor 1x%5E2y%5E2%2B3xy-7xy-21 by grouping:


%281x%5E2y%5E2%2B3xy%29%2B%28-7xy-21%29 Group like terms


xy%28xy%2B3%29-7%28xy%2B3%29 Factor out the GCF of xy out of the first group. Factor out the GCF of -7 out of the second group


%28xy-7%29%28xy%2B3%29 Since we have a common term of xy%2B3, we can combine like terms

So 1x%5E2y%5E2%2B3xy-7xy-21 factors to %28xy-7%29%28xy%2B3%29


So this also means that 1x%5E2y%5E2-4xy-21 factors to %28xy-7%29%28xy%2B3%29 (since 1x%5E2y%5E2-4xy-21 is equivalent to 1x%5E2y%5E2%2B3xy-7xy-21)



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So our expression goes from x%5E8y%28x%5E2y%5E2-4xy-21%29 and factors further to x%5E8y%28xy-7%29%28xy%2B3%29


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Answer:

So x%5E10y%5E3-4x%5E9y%5E2-21x%5E8y factors to x%5E8y%28xy-7%29%28xy%2B3%29