SOLUTION: factoring: Problem - 3x^2 + 243 First answer 3(x^2 + 81)and then I put 3(x + 9) * (x

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Question 146143This question is from textbook
: factoring: Problem - 3x^2 + 243
First answer 3(x^2 + 81)and then
I put 3(x + 9) * (x - 9), is this correct? This question is from textbook

Found 3 solutions by jim_thompson5910, solver91311, Earlsdon:
Answer by jim_thompson5910(35256)   (Show Source):
You can put this solution on YOUR website!
Is there a negative in front of the ???

If there isn't a negative and the problem is :

The step is correct. However, you cannot factor further. So this means that completely factors to

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If there is and the problem is

Start with the given expression

Factor out the GCF

Factor using the difference of squares

So completely factors to

Answer by solver91311(24713)   (Show Source):
You can put this solution on YOUR website!
Right idea, but you have a sign error. Factor out , so that the resulting binomial is the difference of two squares, that is: . Your result should be: . The sum of two squares never factors; the roots of are always imaginary.

Answer by Earlsdon(6294)   (Show Source):
You can put this solution on YOUR website!
Er...not quite right!
Your first step is ok, but that leaves you with the sum of squares binomial which does not have real factors.
However, is that a negative sign in front of the ?, if it is, then you can factor as follows:
=
When you factor the sum of squares binomial you get where:

SOLUTION: factoring: Problem - 3x^2 + 243 First answer 3(x^2 + 81)and then I put 3(x + 9) * (x - 9), is this correct?