SOLUTION: (1) Find 3 consecutive ingtegers if twice the second increased by first is 35. (2) Find 3 consecutive odd numbers whose sum is 171.

Algebra ->  Polynomials-and-rational-expressions -> SOLUTION: (1) Find 3 consecutive ingtegers if twice the second increased by first is 35. (2) Find 3 consecutive odd numbers whose sum is 171.       Log On


   

Question 143389: (1) Find 3 consecutive ingtegers if twice the second increased by first is 35.



(2) Find 3 consecutive odd numbers whose sum is 171.




Answer by solver91311(24713) About Me  (Show Source):
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First integer: x
Second integer: x + 1
Third integer: x + 2

Twice the second: 2(x + 1)
...and increased by the first: 2(x + 1) + x

is (meaning equals) 35, so:

2%28x+%2B+1%29%2Bx=35. Just solve for x to get the first integer and the other two follow.

3 consecutive odd integers whose sum is 171.

First odd integer: x
Second odd integer: x + 2
Third odd integer: x + 4, so

x+%2B+x+%2B+2+%2B+x+%2B+4+=+171, solve for x to get the first integer.