SOLUTION: How to you factor trinomials ? Need to be explained Thanks alot ~!~

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Question 138: How to you factor trinomials ? Need to be explained
Thanks alot ~!~

Answer by KMST(5484) About Me  (Show Source):
You can put this solution on YOUR website!
STRATEGIES TO FACTOR TRINOMIALS:
If your trinomial looks like x%5E2mx%2Bn where m and n are integers, you start by looking for factors of n ,
because if you are going to find factors %28x%2Ba%29 and %28x%2Bb%29 whose product is the trinomial,
you need to find a and b .
In that case, x%5E2mx%2Bn=%28x%2Ba%29%28x%2Bb%29=x%5E2%2Bbx%2Bax%2Bab=x%5E2%2B%28a%2Bb%29x%2Bab for every value of x ,
so a and b must be such that n=ab and m=a%2Bb
If you have x%5E2%2B4x-12=x%5E2%2Bred%284%29%2Bgreen%28-12%29 , you look for a and b such that ab=green%28-12%29 , and a%2Bb=red%284%29 .
To start, you need factors whose product is 12 .
Those are:
12=1%2A12 ,
12=2%2A6 , and
12=3%2A4 .

Then, you will have to give one of the factors a minus sign, to make the product ab=green%28-12%29 .
The factors (with their signs) have to add up to a%2Bb=red%284%29 .
12 and -1 do not work,
because 12%2B%28-1%29=11%3C%3E4 , but
6%2B%28-2%29=4 work, so 6 and -2 are your a and b .
It does not matter which one is a, or which one is in the first factor.
x%5E2%2B4x%2B12=%28x%2B6%29%28x-2%29 or x%5E2%2B4x%2B12=%28x-2%29%28x%2B6%29 is your factoring, anyway you look at it.

What if there is a coefficient before x%5E2, like p%3C%3E1 ?
So, let's say that your trinomial is px%5E2%2Bmx%2Bn .
That changes things a bit.
You could say the factoring could be p%28x%2Ba%29%28x%2Bb%29=p%28x%5E2%28a%2Bb%29x%2Bab%29
%22=%22px%5E2%2Bp%28a%2Bb%29x%2Bpab=highlight%28px%5E2%2B%28pa%2Bpb%29x%2Bpab%29 .
Then, highlight%28n=pab%29 --> highlight%28p%2An=pa%2Apb%29 ,
and you want to factor pn to begin,
to find factors pa and pb such than pa%2Bpb=m .

Let me show you an example:
Let's say I want to factor 6x%5E2-11x-10 , with p=-6 , m=-11 , and n=-10 ,
We calculate p%2An=pa%2Apb=-60 , and look for factor pa and pb such that pa%2Bpb=-11 .
I should start by finding factors of p%2An=6%2A%28-10%29=-60 ,
but I will find the factor pairs with a product of 60 first,
and figure positive or negative signs later.

1%2A60=60 , but that does not work, because 1%2B%28-60%29=-59%3C%3E-11 ,
2%2A30=60 , but that does not work, because 2%2B%28-30%29=-28%3C%3E-11 ,
3%2A20=60 , but that does not work, because 3%2B%28-20%29=-17%3C%3E-11 ,
4%2A15=60 , and that works, because 4%2B%28-15%29=-11 ,
so p%2An=pa%2Apb=-60 , pa and pb are 4 , and -15 .

I write the trinomial px%5E2%2B%28pa%2Bpb%29x%2Bpab ,
from what I found before, as,
6x%5E2%2B%284-15%29x-10=6x%5E2-15x%2B4x-10 and factor once in pairs,
and then factor once more to get the full factorization:
6x%5E2-15x%2B4x-10=3x%282x-5%29%2B2%282x-5%29=%283x%2B2%29%282x-5%29
IN GENERAL:
A trinomial is an expression that is the sum of 3 terms.
In math, when we talk about factoring trinomials,
we usually mean factoring polynomials of degree 2 with 3 terms, like 3x%5E2%2B5x-1 .

CAUTION:
If you are asked to factor a trinomial in algebra class,
it is likely that it will be possible and not too difficult,
but not all degree 2 trinomials can be factored.
Some are the product of 2 nice looking binomial factors.
For example, 3x%5E2%2B5x-2=%283x-1%29%28x%2B2%29 is the product of two binomial factors.
However, when we are working with only real numbers,
not all polynomials of degree 2 with 3 terms can be factored.
Some cannot be factored into factors with real coefficients.
Other can be written as a product of two factors including real numbers as coefficients, but those factors do not look nice,
as in x%5E2-2x-2=%28x-1-sqrt%283%29%29%28x-1%2Bsqrt%283%29%29 .