SOLUTION: I have 2 problems that I am stumped on
x^2-xy/y times y^2/2x-2y how do I cancel the GCF
----------- ----------- ----------- ----------- ----------- ----------
[(x^2-xy)/y]*[y^2/
Algebra ->
Polynomials-and-rational-expressions
-> SOLUTION: I have 2 problems that I am stumped on
x^2-xy/y times y^2/2x-2y how do I cancel the GCF
----------- ----------- ----------- ----------- ----------- ----------
[(x^2-xy)/y]*[y^2/
Log On
Question 129035: I have 2 problems that I am stumped on
x^2-xy/y times y^2/2x-2y how do I cancel the GCF
----------------------------------------------------------------------
[(x^2-xy)/y]*[y^2/(2x-2y)]
[x(x-y)/y]*[y^2/2(x-y)] now cancel out the (x-y) & one of the y terms.
x*y/2=xy/2 answer.
(