SOLUTION: Hello, Can someone help me with this problem. I cant seem to get it. 2x + 6 ----------- 4x^2 + 12x I wasnt sure how to put the exponent in so i put it as ^2

Algebra ->  Polynomials-and-rational-expressions -> SOLUTION: Hello, Can someone help me with this problem. I cant seem to get it. 2x + 6 ----------- 4x^2 + 12x I wasnt sure how to put the exponent in so i put it as ^2      Log On


   

Question 127499: Hello,
Can someone help me with this problem. I cant seem to get it.
2x + 6
-----------
4x^2 + 12x
I wasnt sure how to put the exponent in so i put it as ^2
Found 3 solutions by checkley71, stanbon, bucky:
Answer by checkley71(8403) About Me  (Show Source):
You can put this solution on YOUR website!
(2x+6)/(4x^2+12x)
2(x+3)/4x(x+3)
1/2x answer.

Answer by stanbon(75887) About Me  (Show Source):
You can put this solution on YOUR website!
2x + 6
-----------
4x^2 + 12x
====================
(2(x+3)) / (4x(x+3))
Cancel to get:
= 1/x
========
Cheers,
Stan H.

Answer by bucky(2189) About Me  (Show Source):
You can put this solution on YOUR website!
Given:
.
%282x+%2B+6%29%2F%284x%5E2+%2B+12x%29
.
To simplify this, start with the numerator and factor 2 from each of its terms to get:
.
%282%2A%28x+%2B+3%29%29%2F%284x%5E2+%2B+12x%29
.
Next go to the denominator and factor 4x from each of its terms to change the problem to:
.
%282%2A%28x+%2B+3%29%29%2F%284x%2A%28x+%2B+3%29%29
.
Notice now that the term (x + 3) is common to the numerator and the denominator so it can be
canceled out as follows:
.
%282%2A%28cross%28x+%2B+3%29%29%29%2F%284x%2A%28cross%28x+%2B+3%29%29%29
.
and you are left with:
.
2%2F%284x%29
.
But the 2 in the numerator divides into the 4 of the denominator 2 times. So this term
reduces to:
.
1%2F%282x%29
.
and this is the simplified form of what you were originally given.
.
Hope this helps you to understand the problem.
.