SOLUTION: A function is given. What is the minimum value of the function?
𝑓(𝑥)=3𝑥^2 −11𝑥+𝐶, 5≤𝑥≤10, 𝐶 is a constant
(A)𝑓(5) (B) 𝑓(10) (C) 𝑓(11/3) (D)
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-> SOLUTION: A function is given. What is the minimum value of the function?
𝑓(𝑥)=3𝑥^2 −11𝑥+𝐶, 5≤𝑥≤10, 𝐶 is a constant
(A)𝑓(5) (B) 𝑓(10) (C) 𝑓(11/3) (D)
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Question 1189469: A function is given. What is the minimum value of the function?
𝑓(𝑥)=3𝑥^2 −11𝑥+𝐶, 5≤𝑥≤10, 𝐶 is a constant
(A)𝑓(5) (B) 𝑓(10) (C) 𝑓(11/3) (D) 𝑓(11/6) (E) none of the above. Answer by ikleyn(52776) (Show Source):
x-coordinate of the vertex is x = " " = = = 1.8333...
To the right from this point on x-axis, this quadratic function increases monotonically,
so its minimum value in the given interval/segment is at x=5, i.e. f(5). ANSWER
Option (A).
