SOLUTION: Hi to all, please help me solve these following equations with solution: How many possible zeros of the given equation x^4- 2x^3 - 8x^2 +12x + 16 = 0? a. ) 2 b.) 3 c. ) 4 d.) 5

Algebra ->  Polynomials-and-rational-expressions -> SOLUTION: Hi to all, please help me solve these following equations with solution: How many possible zeros of the given equation x^4- 2x^3 - 8x^2 +12x + 16 = 0? a. ) 2 b.) 3 c. ) 4 d.) 5       Log On


   

Question 1172864: Hi to all, please help me solve these following equations with solution:
How many possible zeros of the given equation x^4- 2x^3 - 8x^2 +12x + 16 = 0?
a. ) 2 b.) 3 c. ) 4 d.) 5
What are the possible zeros of the equation x4 - 2x^3 - 3x^2 + 4x + 4 = 0
a. ) ( x - 2)^2 ( x +1 )^2 b.) ( x +3 )^2 ( x +1 )^2
c. ) ( x +1 )^( x +2 )^2 d.) ( x - 2 )^2 ( x - 2 )^2
Answer by ewatrrr(24785) About Me  (Show Source):
You can put this solution on YOUR website!


Hi  

How many possible zeros of the given equation x^4- 2x^3 - 8x^2 +12x + 16 = 0?

4th Degree Equation:  d) 4 possible solutions. 

Solving or Using a Solver... the result would be 2 real and 2 imaginary roots



What are the possible zeros of the equation x^4 - 2x^3 - 3x^2 + 4x + 4 = 0

a.) ( x - 2)^2 ( x +1 )^2

Multiply:

(x^2 - 4x + 4)

(x^2 +2x + 1) = x^4 - 2x^3 - 3x^2 + 4x + 4

Or one can verify with an online 4th Degree Equation Solver

Wish You the Best in your Studies.