Question 116018: Describe the transformations on the following graph of f(x)=e^x.
State the placement of the horizontal asymptote and y-intercept after the transformation. For example, “left 1” or “rotated about the y-axis” are descriptions.
b) h(x)=e^(-x)
Answer by jim_thompson5910(35256) (Show Source):
You can put this solution on YOUR website! b)
Description of transformation:
Looking at , notice how the exponent is negated. So let's see what affect this transformation has on ,
Start with the given transformation
Plug in x=-2
Negate to get 2
Notice if we plug in x=2 into , we get
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Start with the given transformation
Plug in x=-1
Negate to get 1
Remove the exponent of 1
Notice if we plug in x=1 into , we get
So if we take the opposite of x (to get -x), and plug that into g(x), we'll get the same f(x) answer.
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Answer:
So what this does is simply reflect the entire graph over the y-axis
Notice if we graph and , we get
Graph of (red) and (green)
and we can visually verify the transformation
Horizontal Asymptote:
Since we reflected the graph with respect to the y-axis, the horizontal asymptote of is the same as (you can see this from the graph above)
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Answer:
So the horizontal asymptote is
Note: you can visually verify this answer by looking at the graph above
y-intercept in (x, y) form:
Since the line of symmetry between the two graphs is the line x=0 (ie the y axis), this means that the point that intersects with the y-axis is reflected to itself. So essentially the y-intercept does not change also. Once again, you can visually verify this using the graph above.
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Answer:
So the y-intercept is (0,1)
Once again, you can visually verify this answer by looking at the graph above
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