SOLUTION: 2/X+3-3X+5/X^2+4X+3=5/X+1
I keep getting negetative three but when i plug it in it doesn't work and i dont know how else i can solve it can you PLEASEE help!!!
Algebra ->
Polynomials-and-rational-expressions
-> SOLUTION: 2/X+3-3X+5/X^2+4X+3=5/X+1
I keep getting negetative three but when i plug it in it doesn't work and i dont know how else i can solve it can you PLEASEE help!!!
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Question 115764: 2/X+3-3X+5/X^2+4X+3=5/X+1
I keep getting negetative three but when i plug it in it doesn't work and i dont know how else i can solve it can you PLEASEE help!!! Answer by stanbon(75887) (Show Source):
You can put this solution on YOUR website! 2/(X+3)-(3X+5)/(X^2+4X+3) =5/(X+1)
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lcm = (x+3)(x+1) which is x^2+4x+3
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Multiply thru by the lcm to get:
2(x+1) - (3x+5) = 5(x+3)
2x+2 -3x-5 = 5x+15
6x = -18
x = -3
But x cannot be -3 for that would make the 1st fraction's denominator be zero.
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Therefore: there is no solution to the original equation.
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Cheers,
Stan H.
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