SOLUTION: Factor completely. 2p squared + 11p + 12

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Question 115002: Factor completely.
2p squared + 11p + 12

Answer by jim_thompson5910(35256) About Me  (Show Source):
You can put this solution on YOUR website!

Looking at 2p%5E2%2B11p%2B12 we can see that the first term is 2p%5E2 and the last term is 12 where the coefficients are 2 and 12 respectively.

Now multiply the first coefficient 2 and the last coefficient 12 to get 24. Now what two numbers multiply to 24 and add to the middle coefficient 11? Let's list all of the factors of 24:



Factors of 24:
1,2,3,4,6,8,12,24

-1,-2,-3,-4,-6,-8,-12,-24 ...List the negative factors as well. This will allow us to find all possible combinations

These factors pair up and multiply to 24
1*24
2*12
3*8
4*6
(-1)*(-24)
(-2)*(-12)
(-3)*(-8)
(-4)*(-6)

note: remember two negative numbers multiplied together make a positive number


Now which of these pairs add to 11? Lets make a table of all of the pairs of factors we multiplied and see which two numbers add to 11

First NumberSecond NumberSum
1241+24=25
2122+12=14
383+8=11
464+6=10
-1-24-1+(-24)=-25
-2-12-2+(-12)=-14
-3-8-3+(-8)=-11
-4-6-4+(-6)=-10



From this list we can see that 3 and 8 add up to 11 and multiply to 24


Now looking at the expression 2p%5E2%2B11p%2B12, replace 11p with 3p%2B8p (notice 3p%2B8p adds up to 11p. So it is equivalent to 11p)

2p%5E2%2Bhighlight%283p%2B8p%29%2B12


Now let's factor 2p%5E2%2B3p%2B8p%2B12 by grouping:


%282p%5E2%2B3p%29%2B%288p%2B12%29 Group like terms


p%282p%2B3%29%2B4%282p%2B3%29 Factor out the GCF of p out of the first group. Factor out the GCF of 4 out of the second group


%28p%2B4%29%282p%2B3%29 Since we have a common term of 2p%2B3, we can combine like terms

So 2p%5E2%2B3p%2B8p%2B12 factors to %28p%2B4%29%282p%2B3%29


So this also means that 2p%5E2%2B11p%2B12 factors to %28p%2B4%29%282p%2B3%29 (since 2p%5E2%2B11p%2B12 is equivalent to 2p%5E2%2B3p%2B8p%2B12)