SOLUTION: A chemical company makes two brands of antifreeze. The first brand is
35%
pure antifreeze, and the second brand is
85%
pure antifreeze. In order to obtain
50
gallons of
Algebra ->
Polynomials-and-rational-expressions
-> SOLUTION: A chemical company makes two brands of antifreeze. The first brand is
35%
pure antifreeze, and the second brand is
85%
pure antifreeze. In order to obtain
50
gallons of
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Question 1120960: A chemical company makes two brands of antifreeze. The first brand is
35%
pure antifreeze, and the second brand is
85%
pure antifreeze. In order to obtain
50
gallons of a mixture that contains
65%
pure antifreeze, how many gallons of each brand of antifreeze must be used?
An easy way to solve mixture problems like this, in which two ingredients are being mixed, is to use the fact that the ratio in which the two ingredients must be mixed is exactly determined by where the percentage of the mixture lies between the percentages of the two ingredients.
The percentages of the two ingredients are 35% and 85%; the percentage of the mixture is 65%.
65% is three-fifths of the way from 35% to 85%. (65-35 = 30; 85-35 = 50; 30/50 = 3/5)
So 3/5 of the mixture must be the ingredient with the higher percentage of antifreeze.
So 3/5 of the 50 gallons, or 30 gallons, should be the 85% antifreeze; the other 2/5, or 20 gallons, should be the 35% antifreeze.
You can put this solution on YOUR website! Let = gallons of 35% antifreeze needed
Let = gallons of 85% antifreeze needed
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And
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20 gallons of 35% antifreeze are needed
30 gallons of 85% antifreeze are needed
