Question 1120112: solve the equation by the method of factoring: 4x^3+6x^2=70x
Answer by greenestamps(13198) (Show Source):
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4x^3+6x^2 = 70x
Get all terms on one side, with "0" on the other side:
4x^3+6x^2-70x = 0
Divide by the constant factor 2:
2x^3+3x^2-35x = 0
Factor out the common power of the variable:
x(2x^2+3x-35) = 0
Factor the remaining quadratic factor:
x(2x-7)(x+5) = 0
The solutions are when any of the factors on the left are zero:
x = 0
2x-7 = 0 --> x = 7/2
x+5 = 0 --> x = -5
Answer: The roots are -5, 0, and 7/2.
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