SOLUTION: Reuben rented a truck for one day. There was a base fee of $15.99 , and there was an additional charge of 94 cents for each mile driven. Reuben had to pay $170.15 when h

Algebra ->  Polynomials-and-rational-expressions -> SOLUTION: Reuben rented a truck for one day. There was a base fee of $15.99 , and there was an additional charge of 94 cents for each mile driven. Reuben had to pay $170.15 when h      Log On


   



Question 1116447: Reuben rented a truck for one day. There was a base fee of
$15.99
, and there was an additional charge of
94
cents for each mile driven. Reuben had to pay
$170.15
when he returned the truck. For how many miles did he drive the truck?

Found 2 solutions by josgarithmetic, stanbon:
Answer by josgarithmetic(39617) About Me  (Show Source):
You can put this solution on YOUR website!
Simple linear equation application.
0.94x%2B15.99=170.15
Solve for x.

Answer by stanbon(75887) About Me  (Show Source):
You can put this solution on YOUR website!
Reuben rented a truck for one day. There was a base fee of
$15.99
, and there was an additional charge of
94
cents for each mile driven. Reuben had to pay
$170.15
when he returned the truck. For how many miles did he drive the truck?
----
Cost Equation:: C(m) = 15.99 + 0.94m
----
Solve:: 15.99 + 0.94m = 170.15
-----
0.94m = 154.16
m = 164 miles
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Cheers,
Stan H.
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