SOLUTION: graph p(x)=6x^2(x-4)^3+(x+1)^4

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Question 1116233: graph p(x)=6x^2(x-4)^3+(x+1)^4
Found 2 solutions by greenestamps, ikleyn:
Answer by greenestamps(13198) About Me  (Show Source):
You can put this solution on YOUR website!


9th degree polynomial with a positive leading coefficient; quadruple root at x = -1; double root at x = 0; and triple root at x = 4. So

(1) function value is negative for large negative values of x;
(2) quadruple root (even degree) at x=-1, so the graph touches the x-axis there but the function value then remains negative;
(3) double root (again even degree) at x=0, so again the graph touches the x-axis there and then the function value again remains negative;
(4) triple root (odd degree) at x=4, so the graph crosses the x-axis there and the function value becomes positive

There are no roots larger than x=4, so the function value then remains positive to the right of that point.

The graph...

graph%28400%2C400%2C-2%2C6%2C-50%2C50%2C6x%5E2%28x-4%29%5E3%28x%2B1%29%5E4%29

Answer by ikleyn(52778) About Me  (Show Source):
You can put this solution on YOUR website!
.
Tutor @greenestamps (who usually produced perfect solutions) misread the condition and presented the plot incorrectly.


Below find the correct plot.