SOLUTION: (8x^3 - 6x^2 - 7x + 1)/(2x-3)

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Question 1115925: (8x^3 - 6x^2 - 7x + 1)/(2x-3)
Answer by josgarithmetic(39617) About Me  (Show Source):
You can put this solution on YOUR website!
You start the same way as if normal base-ten numbers division:

       __________________________________________
2x-3   |    8x^3     -6x^2     -7x     +1
       |
       |


The entire process:
             4x^2      3x       1
       __________________________________________
2x-3   |    8x^3     -6x^2     -7x     +1
       |
       |    8x^3     -12x^2
        --------------------
            0         6x^2    -7x
                      6x^2   -9x
                     --------------
                       0      2x    +1
                              2x   -3
                              -----------
                              0     4

QUOTIENT: 4x%5E2%2B3x%2B1
REMAINDER: 4

MEANING: 4x%5E2%2B3x%2B1%2B4%2F%282x-3%29