SOLUTION: Find the zeros of f(x)=2x^3-4x^2-5x+1. You are given (x+1)=-1 as azero.

Algebra ->  Polynomials-and-rational-expressions -> SOLUTION: Find the zeros of f(x)=2x^3-4x^2-5x+1. You are given (x+1)=-1 as azero.       Log On


   

Question 1114756: Find the zeros of f(x)=2x^3-4x^2-5x+1. You are given (x+1)=-1 as azero.
Answer by josgarithmetic(39617) About Me  (Show Source):
You can put this solution on YOUR website!
This is a bad way to say it:
--
(x+1)=-1 as a zero.
--

Just say, either x+1 is a factor of f; or say that -1 is a zero of f. 

-1   |   2   -4   -5   1
     |
     |       -2    6   -1
     |__________________________
        2   -6     1    0

f%28x%29=%28x%2B1%29%282x%5E2-6x%2B1%29
and next yhou want to factorize or find zeros of the quadratic factor.

Zeros for the quadratic factor
%286%2B-+sqrt%2836-4%2A2%29%29%2F4
%286%2B-+sqrt%2828%29%29%2F4
%286%2B-+2%2Asqrt%287%29%29%2F4
highlight%28%283%2B-+sqrt%287%29%29%2F2%29-------the two other real but irrational roots. (zeros)