SOLUTION: There are two triples of positive integers (a,b,c and d,e,f) such that {{{ a^2+b^2+c^2=86 }}} and {{{ d^2+e^2+f^2=86 }}}. Evaluate the expression |abc-def|.

Algebra ->  Polynomials-and-rational-expressions -> SOLUTION: There are two triples of positive integers (a,b,c and d,e,f) such that {{{ a^2+b^2+c^2=86 }}} and {{{ d^2+e^2+f^2=86 }}}. Evaluate the expression |abc-def|.      Log On


   



Question 1107089: There are two triples of positive integers (a,b,c and d,e,f) such that +a%5E2%2Bb%5E2%2Bc%5E2=86+ and +d%5E2%2Be%5E2%2Bf%5E2=86+. Evaluate the expression |abc-def|.
Answer by ikleyn(52754) About Me  (Show Source):
You can put this solution on YOUR website!
.
1)  86 = 1^2 + 2^2 + 9^2


2)  86 = 5^2 + 5^2 + 6^2.


So these two triples are (1,2,9)  and  (5,5,6).


You do the rest.

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And remember:  I just did  99.99%  of the job.