SOLUTION: Question 54. This is dealing with adding/subtracting rational expressions
(the below are supposed to be fractions, but I didn't know how to write them in here so you'd underst
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(the below are supposed to be fractions, but I didn't know how to write them in here so you'd underst
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Question 106371This question is from textbook Beginning Algebra
: Question 54. This is dealing with adding/subtracting rational expressions
(the below are supposed to be fractions, but I didn't know how to write them in here so you'd understand. Sorry if it doesn't come across pretty)
2 - 3
___ ___
5w+10 2w-4
This is what I have so far, but I am a bit confused.
I know that I need to find the LCD. Because of the numerators the way they are, I know that they are:
5w+10 which can be factored to 5(w+2)
2w-4 which can be factored to 2(w-2)
So, still they don't match as they have in other equations.
2*2(w-2) - 3*5(w+2)
___________ __________
5(w+2)*2(w-2) 2(w-2)*5(w+2) Not sure if I did that right
This then becomes:
4(w-2) - 15(w+2)
_________ __________
5(w+2)*2(w-2) 2(w-2)*5(w+2)
I am going to stop there, because I have a horrible feeling that I am way off track. Can you please help? This question is from textbook Beginning Algebra
You can put this solution on YOUR website! 2 - 3
___ ___
5w+10 2w-4
-----------------
Factor the denominators:
[2/(5(w+2)] - [3/(2(w-2)]
----------
You need a common denominator.
-------------
The least common denominator (lcd) is 10(w+2)(w-2)
---------------
Rewrite each fraction with the lcd as its denominator:
-----------
[2*2(w-2)]/lcd - [3*5(w+2)]/lcd
---------------
Since the denominators are now the same you work with the numerators:
= [4(w-2)-15(w+2)]/lcd
Simplify the numerator:
= [-11w-38]/[10(w+2)(w-2)
This could be written as:
= [-11w-38]/[10(w^2-4)]
=================
Cheers,
Stan H.
You can put this solution on YOUR website!
You were spot on as far as you went, I think you needed to recognize that
or, as it applies to your situation:
hence, you end up with the following ugliness:
Simplifying as much as possible yields:
(