SOLUTION: f(x)=32x^3-52x^2+17x+3 who do we list the possible rational zeros of f and can it be discarded and are there more than one zero's?

Algebra ->  Polynomials-and-rational-expressions -> SOLUTION: f(x)=32x^3-52x^2+17x+3 who do we list the possible rational zeros of f and can it be discarded and are there more than one zero's?      Log On


   

Question 105829: f(x)=32x^3-52x^2+17x+3 who do we list the possible rational zeros of f and can it be discarded and are there more than one zero's?
Answer by Fombitz(32388) About Me  (Show Source):
You can put this solution on YOUR website!
f%28x%29=32x%5E3-52x%5E2%2B17x%2B3
I'm not sure of the questions (discarded?).
Looking at the graph, there are three zeros.
One of them is at x=1.
f%281%29=32%281%29%5E3-52%281%29%5E2%2B17%281%29%2B3=32-52%2B17%2B3=0
Another between -1 and 0. The third between 0 and 1.
Hopefully this will help.
Please re-post your question.
+graph%28+300%2C+300%2C+-1%2C+2%2C+-5%2C+5%2C+32x%5E3-52x%5E2%2B17x%2B3%29