SOLUTION: I have the formula h(x)= x^3+5x^2+12x-18 where 1 is a zero. How do I express h(x) as a product of linear factors?

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Question 1052898: I have the formula h(x)= x^3+5x^2+12x-18 where 1 is a zero. How do I express h(x) as a product of linear factors?
Found 3 solutions by josgarithmetic, ikleyn, advanced_Learner:
Answer by josgarithmetic(39613)   (Show Source):
You can put this solution on YOUR website!
The value, 1, being a zero, means that one binomial factor of h is . Divide h(x) by , and factorize the resulting quadratic quotient to finish the factorization of h.

Answer by ikleyn(52752)   (Show Source):
You can put this solution on YOUR website!
.
You are an absolute champion.

I never saw such a picturesque term ". . . 1 is a zero".

It was never used in math.

The correct term is ". . . 1 is a root".

Answer by advanced_Learner(501)   (Show Source):
You can put this solution on YOUR website!
as a product of linear factors
given 1 is a root
x^2 +6x+18
----------------------
x-1 x^3+5x^2+12x-18
x^3-x^2
---------------
0 +6x^2+12x
6x^2-6x
-----------------
0+18x-18
18x-18
------------------
0 0 0
=*
=*