SOLUTION: PLEASE HELP!! use the Intermediate Value Theorem to verify that P has a zero between a and b. P(x)=3x^3+7x^2+3x+7; a= -3, b= -2

Algebra ->  Polynomials-and-rational-expressions -> SOLUTION: PLEASE HELP!! use the Intermediate Value Theorem to verify that P has a zero between a and b. P(x)=3x^3+7x^2+3x+7; a= -3, b= -2      Log On


   

Question 1051064: PLEASE HELP!!
use the Intermediate Value Theorem
to verify that P has a zero between a and b.
P(x)=3x^3+7x^2+3x+7; a= -3, b= -2
Found 2 solutions by Fombitz, ewatrrr:
Answer by Fombitz(32388) About Me  (Show Source):
You can put this solution on YOUR website!
3%28-3%29%5E3%2B7%28-3%29%5E2%2B3%28-3%29%2B7=-81%2B63-9%2B7=-20
3%28-2%29%5E3%2B7%28-2%29%5E2%2B3%28-2%29%2B7=-24%2B28-6%2B7=5
Since the function value goes from -20 to 5 in the interval between -3 and -2, there must exist a value of x between -3 and -2 where the function equals zero.

Answer by ewatrrr(24785) About Me  (Show Source):
You can put this solution on YOUR website!
P(x)=3x^3+7x^2+3x+7; a= -3, b= -2
P(-3) = -20
P(-2) = 5
verify that P has a zero between -3 and -2