SOLUTION: If p and q are roots of polynomial equation x^2+x+q=0,then A) p=-1 and q=0 B) p=1 and q=-2 Which condition is true A or B

Algebra ->  Polynomials-and-rational-expressions -> SOLUTION: If p and q are roots of polynomial equation x^2+x+q=0,then A) p=-1 and q=0 B) p=1 and q=-2 Which condition is true A or B      Log On


   

Question 1050824: If p and q are roots of polynomial equation x^2+x+q=0,then A) p=-1 and q=0 B) p=1 and q=-2
Which condition is true A or B
Answer by josgarithmetic(39617) About Me  (Show Source):
You can put this solution on YOUR website!
p AND q are the two roots


x=%28-1%2B-+sqrt%281-4%2Aq%29%29%2F2

system%28x=%28-1-sqrt%281-4q%29%29%2F2%2C++or%2C+x=%28-1%2Bsqrt%281-4q%29%29%2F2%29

(A)
p=-1,q=0

x%5E2%2Bx=0
x%28x%2B1%29=0
Which conditions true?
No problems and no conflicts. Many things may be true. p and q are real roots. Discriminant is greater than 0, as in 1%5E2-4%2A1%2A0=1.

(B)
p=1,q=-2
You can try the substitution and look for something similar in method as in A.
%28x-1%29%28x%2B2%29=0
and simplifying and finding discriminant, this would be also greater than 0.

Using the general solution formula was not necessary. Factorizations were possible.