SOLUTION: What are the factors of 6n^2+2n-5?

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Question 1046761: What are the factors of 6n^2+2n-5?
Found 2 solutions by fractalier, ewatrrr:
Answer by fractalier(6550) About Me  (Show Source):
You can put this solution on YOUR website!
We cannot factor
6n^2 + 2n - 5
using integer factors.
I suspect that either the problem was copied incorrectly or the answer is that it just cannot be factored so.

Answer by ewatrrr(24785) About Me  (Show Source):
You can put this solution on YOUR website!
6n^2+2n-5
Quadratic Equation ALWAYS works.
n=+%28-b+%2B-+sqrt%28+b%5E2-4%2Aa%2Ac+%29%29%2F%282%2Aa%29+
n=+%28-2+%2B-+sqrt%28+2%5E2-+4%2A6%2A%28-5%29%29%29%2F%282%2A6%29+
n=+%28-2+%2B-+sqrt%28+124%29%29%2F%2812%29+
n=+%28-2+%2B-+sqrt%28+4%2A31%29%29%2F%2812%29+
n=+1%2F6+%2B-+%281%2F6%29sqrt%2831%29%29+
List FAcotrs:
a(x − x+)(x − x−)
Factors:
6(x -1%2F6+%2B%281%2F6%29sqrt%2831%29%29+) and 6(x -+1%2F6-%281%2F6%29sqrt%2831%29%29+)
(6x - 1+%2B+sqrt%2831%29%29+) and (6x - +1-sqrt%2831%29%29+)