SOLUTION: I am having a few issues if someone could help. The first problem is
3 with exponent of x+4 = 7 with exponent of 2x-1
Through all my notes I am finding nothing like this, my
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-> SOLUTION: I am having a few issues if someone could help. The first problem is
3 with exponent of x+4 = 7 with exponent of 2x-1
Through all my notes I am finding nothing like this, my
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Question 1042042: I am having a few issues if someone could help. The first problem is
3 with exponent of x+4 = 7 with exponent of 2x-1
Through all my notes I am finding nothing like this, my exmples are where I would take 3 as my base for 2nd equation Answer by stanbon(75887) (Show Source):
You can put this solution on YOUR website! 3 with exponent of x+4 = 7 with exponent of 2x-1
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3^(x+4) = 7^(2x-1)
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Since the variable is in the exponent, take the log::
(x+4)*log(3) = (2x-1)*log(7)
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Now, get the x terms together::
x(log3-2*log(7)) = log(7)-4log(3)
x(-1.213) = -1.063
x = 0.877
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Cheers,
Stan H.
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