Question 1023232: (3m / 2m^2 + 7m - 15) + (6 / 2m^2 - 3m) + (2m + 3 / 2m^2 + 17m + 35)
Answer by KMST(5328)   (Show Source):
You can put this solution on YOUR website! I suspect what you meant is
3m /(2m^2 + 7m - 15) + 6 /(2m^2 - 3m) + (2m + 3) / (2m^2 + 17m + 35) = .
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NOTE:
In the expression 3m/(2m^2 + 7m - 15) + 6/(2m^2 - 3m) + (2m + 3)/(2m^2 + 17m + 35) ,
the very necessary brackets mean that what what is inside them must be calculated first.
So in evaluating that expression for any value of m,
the denominators, and the "2m + 3" numerator are calculated first.
(What would be done next is the three divisions,
and finally you would add the three calculated quotient values).
In the expression ,
those long horizontal lines mean that what is below them (and what is above them) must be calculated first.
Those long horizontal lines have invisible brackets attached,
but when you cannot type those lines, you must put brackets in the right places.
If you put brackets in the wrong places, or leave them out,
you will be misunderstood by computers, most calculators,
and people who the centuries old "grammar rules" of written algebraic expressions.
because
(3m / 2m^2 + 7m - 15) + (6 / 2m^2 - 3m) + (2m + 3 / 2m^2 + 17m + 35) =        = 3m/2m^2 + 7m - 15 + 6/2m^2 - 3m + 2m + 3/2m^2 + 17m + 35 .
If you want to calculate  =8100/(100-19) ,
and get the correct answer,  ,
you must enter "8100 / ( 100 - 19 )" on your calculator or computer.
If you enter it as "8100 / 100 - 19 =" into a calculator,
or enter "= 8100 / 100 - 19" in a spreadsheet in your computer,
you will get what you asked:
8100 / 100- 19 =
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