SOLUTION: find all the complex zeros. f(x)= 2x^4-x^3+7x^2-4x-4 P=+-1,+-2,+-7,+-4 Q=+-2 p/q=+-1,+-2,+-7

Algebra ->  Polynomials-and-rational-expressions -> SOLUTION: find all the complex zeros. f(x)= 2x^4-x^3+7x^2-4x-4 P=+-1,+-2,+-7,+-4 Q=+-2 p/q=+-1,+-2,+-7      Log On


   

Question 1022208: find all the complex zeros. f(x)= 2x^4-x^3+7x^2-4x-4
P=+-1,+-2,+-7,+-4
Q=+-2
p/q=+-1,+-2,+-7
Answer by josgarithmetic(39618) About Me  (Show Source):
You can put this solution on YOUR website!
The coefficient 7 is not involved that way.

p, choose from: -1, -2, -4, 1, 2, 4

q, choose from : -1, -2, 1, 2

Possible roots p/q to check:
-1, -1/2, 1, 1/2, -2, 2, -4, 4
Those are for the possible RATIONAL real roots.

After finding your first two real rational roots, the next two will be possibly two complex roots. The formula for general solution of quadratic equation will be used for this.