SOLUTION: 4.5 Solve the equation x^3 -13x^2 +47x-35=0 given that 1 is a zero of f(x)=x^3 -13x^2 +47x-35 The solution set is { } I got 1,5,7 is this right?

Algebra ->  Polynomials-and-rational-expressions -> SOLUTION: 4.5 Solve the equation x^3 -13x^2 +47x-35=0 given that 1 is a zero of f(x)=x^3 -13x^2 +47x-35 The solution set is { } I got 1,5,7 is this right?      Log On


   

Question 1013999: 4.5
Solve the equation x^3 -13x^2 +47x-35=0 given that 1 is a zero of f(x)=x^3 -13x^2 +47x-35
The solution set is { }

I got 1,5,7 is this right?
Answer by Alan3354(69443) About Me  (Show Source):
You can put this solution on YOUR website!
Solve the equation x^3 -13x^2 +47x-35=0 given that 1 is a zero of f(x)=x^3 -13x^2 +47x-35
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I got 1,5,7 is this right?
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It's right.
You can check it.
If (x-1)*(x-5)*(x-7) = x^3 -13x^2 +47x-35 it's right.
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f(x) = x^3 -13x^2 +47x-35
If f(1) = 0 it's a zero.
Same for f(5) and f(7).