Question 1010273: Please help! I've had trouble with this for a long time and always seem to be stuck on it.
The length of a rectangle is three times the width of the rectangle. If the width of the rectangle is y units, what is the area of the rectangle?
3y units2
3y2 units2
y + 3 units2
3y(y + 3) units2
Found 2 solutions by fractalier, MathTherapy:
Answer by fractalier(6550)   (Show Source):
You can put this solution on YOUR website! Yes. If the width is 10 and the length is three times that, you would say the length is 30. If the width is 20, the length is 60. Right?
So, if the width is y units, the length is three times that too, or 3y units.
Then the area is always length times width, and
A = LW = (3y)(y) = 3y^2 square units
Answer by MathTherapy(10551)  (Show Source):
You can put this solution on YOUR website!
Please help! I've had trouble with this for a long time and always seem to be stuck on it.
The length of a rectangle is three times the width of the rectangle. If the width of the rectangle is y units, what is the area of the rectangle?
3y units2
3y2 units2
y + 3 units2
3y(y + 3) units2
Width: y
Length: 3 * y, or 3y
Area: Width * Length, or y * 3y, or 
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