SOLUTION: R^2 - 5r+6 ----------- -----(over) R^2-4 For all r=positive and negative 2

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Question 1003569: R^2 - 5r+6
-----------------(over)
R^2-4
For all r=positive and negative 2
Answer by KMST(5328) About Me  (Show Source):
You can put this solution on YOUR website!
%28r%5E2-5r%2B6%29%2F%28r%5E2-4%29=%28r-2%29%28r-3%29%2F%28%28r-2%29%28r%2B2%29%29 if it exists/is defined.
For system%28r=-2%2C%22or%22%2Cr=2%29 , the denominator is zero, and the expressions above are undefined.
For all r such that system%28r%3C%3E-2%2C%22and%22%2Cr%3C%3E2%29 , the expression %28r%5E2-5r%2B6%29%2F%28r%5E2-4%29 is defined, and
.