SOLUTION: Two poles are 33 feet and 48 feet high, respectively. A wire is strung from the top of one pole to the top of the other. How long is the wire if the poles are 36 feet apart?
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Question 98833: Two poles are 33 feet and 48 feet high, respectively. A wire is strung from the top of one pole to the top of the other. How long is the wire if the poles are 36 feet apart? Found 2 solutions by Earlsdon, malakumar_kos@yahoo.com:Answer by Earlsdon(6294) (Show Source):
You can put this solution on YOUR website! Assuming that there is no sag in the wire betwwen the two poles (not a realistic situation), then we can make a right triangle in which the wire represents the hypotenuse, the base of the triangle is represented by the distance between the two poles (36ft.) and the height of the triangle is simply the difference between the heights of the two poles (48ft. - 33ft. = 15ft.).
Now you can apply the pythagorean theorem to find the length of the hypotenuse (the length of the wire (W)) Take the square root of both sides. ft.
The length of the wire is 39 feet.
You can put this solution on YOUR website!
Two poles are 33 feet and 48 feet high, respectively. A wire is strung from the top of one pole to the top of the other. How long is the wire if the poles are 36 feet apart?
The height of pole A = 48 ft
The height of pole B = 33 ft
Distance between them = 36 ft
Differnce in the height of the pole = 48-33 = 15 ft
To find the length of the wire apply pythogorus theorem
(Length of the wire)^2 = (36)^2+(15)^2
= 1296 + 225
= 1521
length of the wire = sq.rt of 1521
= 39 ft
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