SOLUTION: the sum of the interior angles of a regular polygon is 540 and side is 5cm .determine the following . no.of sides no.of diagonals no.of triangles central angle interior angle

Algebra ->  Polygons -> SOLUTION: the sum of the interior angles of a regular polygon is 540 and side is 5cm .determine the following . no.of sides no.of diagonals no.of triangles central angle interior angle       Log On


   



Question 928071: the sum of the interior angles of a regular polygon is 540 and side is 5cm .determine the following .
no.of sides
no.of diagonals
no.of triangles
central angle
interior angle
perimeter
area
apotheim

Answer by KMST(5328) About Me  (Show Source):
You can put this solution on YOUR website!
The sum of the measures of the interior angles of a convex polygon with n sides is
%28n-2%29%2A180%5Eo
In this case,
%28n-2%29%2A180%5Eo=540%5Eo-->n-2=540%5Eo%2F180%5Eo-->n-2=3-->n=3%2B2-->highlight%28n=5%29 .
So this regular polygon has highlight%285%29 sides. It is a pentagon.
Five sides means 5 vertices.
Form each vertex you can draw diagonals to other vertices.
There are 6-1=4 other vertices, but the 2 lines connecting to the next vertices to either side are not diagonals, but sides of the polygon.
So, from each vertex, you can draw 5-1-2=2 diagonals connecting to other vertices.
That would add up to 5%2A2=10 diagonals, but we would be counting each diagonal twice, for example once as a line from vertex A to vertex C, and once more as a line from vertex C to vertex A.
So there are just highlight%285%29 possible diagonals .
The 2 diagonals from each vertex split the pentagon into isosceles triangles with a side of the pentagon as a base, and 5 with a diagonal of the pentagon as a base, for a total of 5%2B5=10 large triangles.
We can also figure out that there are 10 different large triangles, because there are highlight%2810%29 different sets of 3 vertices that can be made from the 6 vertices of the pentagon.
The diagonal also form 10 more, smaller triangles with one or two vertices at the intersections of diagonals inside the pentagon.

Connecting the vertices of the regular pentagon to its center we form 5 congruent triangles with 5 angles at the center of the pentagon called "central angles".
Each central angle measures 360%5Eo%2F5=highlight%2872%5Eo%29
The measure of each of the 5 interior angles of the pentagon is
540%5Eo%2F5=highlight%28108%5Eo%29 .
The perimeter of the pentagon is 5%2A%285cm%29=highlight%2825cm%29 .
The area of the regular pentagon can be calculated as the sum of the areas of the 5 isosceles triangles formed by the lines connecting the vertices to the center.
For each of those isosceles triangles, we can take the side of the pentagon as the base, and the line connecting the midpoint of that base to the center of the pentagon as the altitude. The measure of that altitude is the height of the triangle, and the apothem of the regular pentagon.
In general, the area of the regular polygon with n sides is n%2A%28side%2Aapothem%2F2%29=%28n%2Aside%29%2Aapohem%2F2=perimeter%2Aapothem%2F2
apothem=2.5cm%2Ftan%2836%5Eo%29=highlight%283.44cm%29 (rounded), and area=%2825cm%29%283.44cm%29%2F2=highlight%2834%29cm%5E2 .