SOLUTION: iregular pentagon 2 interior angles are 140 and 75 the other 3 are 2x, 3x, 3x+5 what is x and how do i work it out

Algebra ->  Polygons -> SOLUTION: iregular pentagon 2 interior angles are 140 and 75 the other 3 are 2x, 3x, 3x+5 what is x and how do i work it out      Log On


   



Question 881111: iregular pentagon 2 interior angles are 140 and 75 the other 3 are 2x, 3x, 3x+5 what is x and how do i work it out
Answer by Alan3354(69443) About Me  (Show Source):
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iregular pentagon 2 interior angles are 140 and 75 the other 3 are 2x, 3x, 3x+5 what is x and how do i work it out
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The sum of the Int angles of a pentagon is 540 degs 180*(5 - 2)
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140 + 75 + 2x + 3x + 3x+5 = 540