Question 1198365: V-QRST is a rectangular pyramid with edge VS, base QRST. QR = 3/8 m, RS = 5/8 m, and VS = 2/3 m. How many square centimeters are there on its lateral surface? Round off the answer to the nearest integer.
Answer by greenestamps(13198)   (Show Source):
You can put this solution on YOUR website!
Lots of tedious calculations, with numbers that are not "nice" -- I'll leave them to you.
Let P be the center of the rectangular base.
Let X be the midpoint of RS and Y be the midpoint of ST.
The lateral surface of the pyramid consists of triangles RSV and QTV which are congruent, and triangles QRV and STV which are congruent.
(1) Use SX and SY to find SP
(2) Use SP and VS to find the height of the pyramid, VP
(3) Use PV and PX to find VX, the altitude of triangle RSV
(4) Use PV and PY to find VY, the altitude of triangle STV
That gives you all the numbers you need to find the lateral surface area.
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