SOLUTION: The diagonals of a parallelogram meet at K. If AK= 3x+1, KC= x+5, BK= 2x+3, and KD= 4x-1, what kind of parallelogram is ABCD. Why?

Algebra ->  Polygons -> SOLUTION: The diagonals of a parallelogram meet at K. If AK= 3x+1, KC= x+5, BK= 2x+3, and KD= 4x-1, what kind of parallelogram is ABCD. Why?      Log On


   

Question 1164925: The diagonals of a parallelogram meet at K. If AK= 3x+1, KC= x+5, BK= 2x+3, and KD= 4x-1, what kind of parallelogram is ABCD. Why?
Answer by solver91311(24713) About Me  (Show Source):
You can put this solution on YOUR website!


Set the expressions for AK and KC equal to each other because you know that the diagonals of a parallelogram bisect each other. Solve for , then substitute that value in each of the four expressions. Compare the measures of AC and BD. What can you conclude?


John

My calculator said it, I believe it, that settles it