SOLUTION: Find the area of a regular hexagon with the given measurement. apothem = 2 radical 3

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Question 1118750: Find the area of a regular hexagon with the given measurement.
apothem = 2 radical 3

Found 2 solutions by josgarithmetic, ikleyn:
Answer by josgarithmetic(39623)   (Show Source): You can put this solution on YOUR website!
hexagon and apothem....
Hexagon: Regular polygon with six congruent sides.
Apothem: Segment whose endpoints are center of a regular polygon and midpoint of one of the sides.

Draw the description! Can you identify one or two special right triangles which will help you from there?

I do not show a picture here but only describe one this much:
Hexagon is composed of six congruent equilateral triangles. If apothem a is the height, and one side is 2x, then the apothem cuts equilateral triangle into two special 30-60-90 right triangles, each also with leg x.

Your apothem, a is given but x can be solved for...

Can you continue from here?

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.
.
1 equilateral triangle area, .
6 of these to make the hexagon area, .

Answer by ikleyn(52832)   (Show Source): You can put this solution on YOUR website!
.
The area of a regular hexagon is six times the area of central equilateral triangle.


You are given the apothem =  of the regular hexagon, which is the altitude of the equilateral triangle.


Let x be the side length of the hexagon.

It is also the side length of the equilateral triangle.


In an equilateral triangle with the side length x the altitude is  .   //  Every student who study/studied Geometry must know it.


Therefore,   = ,  which implies  x= 4.


Thus the side length of the regular hexagon is 4 units, same as the side length of the equilateral triangle.


Hence, the area of the equilateral triangle is   =  square units.


Then the area of the given hexagon is 6 times this value, i.e.  square units.


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