SOLUTION: find the number of sides of a regular polygon whose interior angle is twice the exterior angle

Algebra ->  Polygons -> SOLUTION: find the number of sides of a regular polygon whose interior angle is twice the exterior angle      Log On


   



Question 1077097: find the number of sides of a regular polygon whose interior angle is twice the exterior angle
Found 2 solutions by 10037376, Alan3354:
Answer by 10037376(2) About Me  (Show Source):
You can put this solution on YOUR website!
Let Interior Angle Be 2x
And Exterior Be x
Sum Of Angle Be 180 degrees
SOLUTION
2x+x=180
3x=180
x=60
;interior angle is 120 degrees
;exterior angle is 60 degrees

Answer by Alan3354(69443) About Me  (Show Source):
You can put this solution on YOUR website!
find the number of sides of a regular polygon whose interior angle is twice the exterior angle
--------
Int + Ext = 180
Int = 2*Ext
--> Ext angles = 60 degs
===========
The sum of exterior angles for ALL convex polygons is 360 degs.
360/60 = 6 sides.