SOLUTION: If the measure of an interior angle of a regular polygon is greater than 150°, what is the least number of sides it can have?
A) 10 B) 11 C) 12 D) 13
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A) 10 B) 11 C) 12 D) 13
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Question 1044879: If the measure of an interior angle of a regular polygon is greater than 150°, what is the least number of sides it can have?
A) 10 B) 11 C) 12 D) 13 Found 2 solutions by addingup, MathTherapy:Answer by addingup(3677) (Show Source):
You can put this solution on YOUR website! how much greater than 150?
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Here is assuming that your polygon's interior angle IS 150:
The exterior angle of a polygon + its corresponding interior angle always add up to 180° (because if you put them together you get a straight line)
(180(n - 2)/n = 150
180n - 360 = 150n
180n - 150n = 360
:
30n = 360
n = 360/30
n = 12 Your polygon would have 12 sides.
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And if your angle is greater than 150? Well, the sum of the interior angles of any polygon increase by 180 with every additional side.
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Oh, and in case you'd like to know, a 12-sided polygon is called a dodecagon
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John
You can put this solution on YOUR website!
If the measure of an interior angle of a regular polygon is greater than 150°, what is the least number of sides it can have?
A) 10 B) 11 C) 12 D) 13
The least number of sides, with each interior ∠ GREATER than = . This DOES NOT reflect any of the 4 choices.
