SOLUTION: Find each measure of each interior angle of nonagon in which the measure of the interior angles are 3x+15, 2x+30, 3x+10, 2x+55, 2x+60, 2x-35, 3x-5, x+40, 2x+70.
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-> SOLUTION: Find each measure of each interior angle of nonagon in which the measure of the interior angles are 3x+15, 2x+30, 3x+10, 2x+55, 2x+60, 2x-35, 3x-5, x+40, 2x+70.
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Question 1034730: Find each measure of each interior angle of nonagon in which the measure of the interior angles are 3x+15, 2x+30, 3x+10, 2x+55, 2x+60, 2x-35, 3x-5, x+40, 2x+70. Answer by Edwin McCravy(20054) (Show Source):
The formula for the sum of the interior angles of an n-sided
polygon is . Add them up and set equal t
the formula with n=9, since a nonagon has 9 sides and 9
interior angles.
Solve for x.
Get x = 51°
Edwin
