We can "look and see" that the line is a secant for
it cuts the circle in two points.
But "look and see" doesn't count in rigorous mathematics,
so we solve the system to find whether there
1. are 2 real solutions, in which case it is a secant, as we suspect,
2. is only 1 real solution, in which case it would be a tangent,
3. are no real solutions (imaginary solutions), in which case
it would be neither (a line totally outside the circle).
Solve the system of the two equations:
Solve the second for y
Substitute for y in the first equation
x=0; 5x+12=0
5x=-12
x=-2.4
If x = 0, then y = 2x+3 = 2(0)+3 = 3
So the line intersects the circle at (x,y) = (0,3)
If x = -2.4, then y = 2x+3 = 2(-2.4)+3 = -4.8+3 = -1.8
So the line intersects the circle also at (x,y) = (-2.4,-1.8)
So the line intersects the circle twice, so it is a secant.
Edwin