Tutors Answer Your Questions about Permutations (FREE)
Question 1135585: There are 4 students attending a test and 7 teachers available for checking the tests.
Each student's test is checked by exactly one of these teachers, with each teacher being equally likely to be the one who checks the test.
The probability that all the 4 papers are checked by exactly 3 teachers is equal to k(6/7)^2.
Click here to see answer by ikleyn(52776)  |
Question 1135585: There are 4 students attending a test and 7 teachers available for checking the tests.
Each student's test is checked by exactly one of these teachers, with each teacher being equally likely to be the one who checks the test.
The probability that all the 4 papers are checked by exactly 3 teachers is equal to k(6/7)^2.
Click here to see answer by kohkche(3) |
Question 1135588: There are 4 students attending a test and 7 teachers available for checking the tests. Each student's test is checked by exactly one of these teachers, with each teacher being equally likely to be the one who checks the test. The probability that all the 4 papers are checked by exactly 3 teachers is k(6/7)^2.
What is the value of k?
(Sorry for leaving out the last part)
Click here to see answer by ikleyn(52776)  |
Question 1135741: A committee is to be formed comprising of 7 member such that there is a majority of men and at least 1 woman in every committee.The shortlist consists of 9 men and 6 women.In how many ways can this be done?
Click here to see answer by VFBundy(438)  |
Question 1135583: Suppose a shipment of 140 electronic components contains 3 defective components. To determine whether the shipment should be accepted, a quality-control engineer randomly selects 3 of the components and tests them. If 1 or more of the components is defective, the shipment is rejected. What is the probability that the shipment is rejected? can you help me solve this with statcrunch
Click here to see answer by Edwin McCravy(20054)  |
Question 1135860: A man has 7 relative.Four of them are ladies and 3 gentleman;his wife also has 7 relatives.Three of them are ladies and 4 gentlemen.IN how many ways can they invite 3 ladies and 3 gentlmen for a dinner party so that there are 3 of the mans relatives and 3 of the wifes relatives?
Click here to see answer by VFBundy(438)  |
Question 1132895: One of the wagers in the game of roulette is to place a bet that the ball will land on a black number. (Eighteen of the numbers are black, 18 are red, and two are green.) If the ball lands on a black number, the player wins the amount of his bet. If a player bets $4, find the player's expectation. (Round your answer to two decimal places.)
Click here to see answer by math_helper(2461)  |
Question 1136197: The eight-person board of directors of the Acme Corporation is to elect a president, a vice-president, and a treasurer, and the remaining members will be a committee to study future expansion. In how many ways can these officers be elected?
Click here to see answer by ikleyn(52776)  |
Question 1136227: A train going from cambridge to London stops at 9 intermediate station.Six person enter the train during the journey with 6 different tickets of the same class.How many different sets of tickets would they hsve?
Click here to see answer by ikleyn(52776)  |
Question 1136460: The human resources department of a consulting firm gives a standard creativity test to a randomly selected group of
new hires every year. This year, 65 new hires took the test and scored a mean of 112.8 points with a standard deviation of 15.6. Last year,
90 new hires took the test and scored a mean of 117.2 points with a standard deviation of. Assume that the population standard deviations of 17.2 the test scores of all new hires in the current year
and the test scores of all new hires last year can be estimated by the sample standard deviations, as the
samples used were quite large. Construct a 95% confidence interval for u1-u2, the difference between the mean test
score u1 of new hires from the current year and the mean test score u2 of new hires from last year. Then
complete the table below.
Carry your intermediate computations to at least three decimal places.
Round your answers to at least two decimal places. (If necessary, consult a list of formulas.)
What is the lower limit of the 95% confidence interval?
What is the upper limit of the 95% confidence interval?
Click here to see answer by Boreal(15235)  |
Question 1136525: Bob is planning to pack 6 shirts and 4 pairs of pants for a trip. If he has 10 shirts and 10 pairs of pants to choose from, in how many different ways can this be done?
side note:
(thank you! this is for an important math class, this is literally saving! thank you again)
Click here to see answer by Boreal(15235)  |
Question 1136585: On this page:
https://www.algebra.com/algebra/homework/Permutations/change-this-name6021.lesson
Why has this been wrong for ten years? The correct answer is 606.
< excerpt from page follows ...
EXAMPLE:
Q. How many different 4 letter "words" can you make from the word DAFFODIL?
A: The number of permutations is P(8,4) since permutations do not distinguish between DAFF and DAFF, for example: If I had written DAFfOdIL instead, you can now see the differences as DAFf and DAfF.
The question is one of permutations and not combinations, since in this example, we are definitely interested in DAFF, ADFF, FFAD, FADF etc being different "words" rather than duplicate versions of the same "combination" of 4 letters.
So, the total number of permutations is 1680. However, 1680 is not the correct answer, since we have 2 D's and 2 F's.
The correct answer is 1680/(2.2) --> 420.
Click here to see answer by ikleyn(52776)  |
Question 1136624: 3. Your community has asked you to help the Young Men's Christian Association (YMCA) sports director organize a season of sports. You need to put together the teams. For the soccer teams, athletes signed up with three different age groups. How many different ways can you organize teams of 10 for each age group
Click here to see answer by ikleyn(52776)  |
Question 1136801: There are nine female board members and twenty-one male board members.
How many ways are there to make a committee of twelve board members if exactly two must be female?
Determine the probability of selecting a committee of twelve board members where exactly two of the members were female. Write your answer as a decimal, rounded to the nearest thousandth.
Click here to see answer by ikleyn(52776)  |
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Older solutions: 1..45, 46..90, 91..135, 136..180, 181..225, 226..270, 271..315, 316..360, 361..405, 406..450, 451..495, 496..540, 541..585, 586..630, 631..675, 676..720, 721..765, 766..810, 811..855, 856..900, 901..945, 946..990, 991..1035, 1036..1080, 1081..1125, 1126..1170, 1171..1215, 1216..1260, 1261..1305, 1306..1350, 1351..1395, 1396..1440, 1441..1485, 1486..1530, 1531..1575, 1576..1620, 1621..1665, 1666..1710, 1711..1755, 1756..1800, 1801..1845, 1846..1890, 1891..1935, 1936..1980, 1981..2025, 2026..2070, 2071..2115, 2116..2160, 2161..2205, 2206..2250, 2251..2295, 2296..2340, 2341..2385, 2386..2430, 2431..2475, 2476..2520, 2521..2565, 2566..2610, 2611..2655, 2656..2700, 2701..2745, 2746..2790, 2791..2835, 2836..2880, 2881..2925, 2926..2970, 2971..3015, 3016..3060, 3061..3105, 3106..3150, 3151..3195, 3196..3240, 3241..3285, 3286..3330, 3331..3375, 3376..3420, 3421..3465, 3466..3510, 3511..3555, 3556..3600, 3601..3645, 3646..3690, 3691..3735, 3736..3780, 3781..3825, 3826..3870, 3871..3915, 3916..3960, 3961..4005, 4006..4050, 4051..4095, 4096..4140, 4141..4185, 4186..4230, 4231..4275, 4276..4320, 4321..4365, 4366..4410, 4411..4455, 4456..4500, 4501..4545, 4546..4590, 4591..4635, 4636..4680, 4681..4725, 4726..4770, 4771..4815, 4816..4860, 4861..4905, 4906..4950, 4951..4995, 4996..5040, 5041..5085, 5086..5130, 5131..5175, 5176..5220, 5221..5265, 5266..5310, 5311..5355, 5356..5400, 5401..5445, 5446..5490, 5491..5535, 5536..5580, 5581..5625, 5626..5670, 5671..5715, 5716..5760, 5761..5805, 5806..5850, 5851..5895, 5896..5940, 5941..5985, 5986..6030, 6031..6075, 6076..6120, 6121..6165, 6166..6210, 6211..6255, 6256..6300, 6301..6345, 6346..6390, 6391..6435, 6436..6480, 6481..6525, 6526..6570, 6571..6615, 6616..6660, 6661..6705, 6706..6750, 6751..6795, 6796..6840, 6841..6885, 6886..6930, 6931..6975, 6976..7020, 7021..7065, 7066..7110, 7111..7155, 7156..7200, 7201..7245, 7246..7290, 7291..7335, 7336..7380, 7381..7425, 7426..7470, 7471..7515, 7516..7560, 7561..7605, 7606..7650, 7651..7695, 7696..7740, 7741..7785, 7786..7830, 7831..7875, 7876..7920, 7921..7965, 7966..8010, 8011..8055, 8056..8100, 8101..8145, 8146..8190, 8191..8235, 8236..8280, 8281..8325, 8326..8370, 8371..8415, 8416..8460, 8461..8505, 8506..8550, 8551..8595, 8596..8640, 8641..8685, 8686..8730, 8731..8775, 8776..8820, 8821..8865, 8866..8910, 8911..8955, 8956..9000, 9001..9045, 9046..9090, 9091..9135, 9136..9180, 9181..9225, 9226..9270, 9271..9315, 9316..9360, 9361..9405, 9406..9450, 9451..9495, 9496..9540, 9541..9585, 9586..9630, 9631..9675, 9676..9720, 9721..9765, 9766..9810, 9811..9855, 9856..9900, 9901..9945, 9946..9990, 9991..10035
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