Tutors Answer Your Questions about Permutations (FREE)
Question 198260: A teacher prepares a test.She gives 5 objective type of questions out of which 4 have to be answered.Find the total ways in which they can be answered if the first 2 have 3 options and last 3 have 4 options?
Click here to see answer by arallie(162)  |
Question 198486: 1) In how many ways can 5 seats on a bench be assigned from amongst 12 people?
2)John and Harry Invited four other people to sit on their bench. In how many ways can these six people be seated on this bench if:
a)there are no restrictions
b)john is seated at the left end and Harry is seated at the right end
c)John and Harry must be seated together.
3)You bought five house numbers at your lumber supply store. The numbers are 1,2,3,4 and 5.How many three-digit house numbers a)are even? b)are possible?
Click here to see answer by stanbon(75887) |
Question 199754: May someone can help me with:
In how many ways can 2 men, 4 women, 3 boys, 3 girls be selected from 6 men, 8 women, 4 boys and 5 girls if a particular man and a particular woman must be selected?
The answer is 7000 but I get 14000:
{5!/(2!3!)} x {7!/(4!3!)} x {4!/3!} x {5!/(2!3!)}
for the men, I take 5! because there are (6-1) men remaining: one has been selected already;
for the women, I take 7! because there are (8-1) women remaining: one has been selected already;
Thanks a lot!
Click here to see answer by solver91311(24713)  |
Question 199877: This is the last problem that i missed on my exam please help me .. so I will have it straigh for my final. thank you T-Aun
How many different ways are there for an admissions officer to select a group of 6 college candidates from a group of 15 applicants for an interview?
Click here to see answer by rfer(16322) |
Question 199877: This is the last problem that i missed on my exam please help me .. so I will have it straigh for my final. thank you T-Aun
How many different ways are there for an admissions officer to select a group of 6 college candidates from a group of 15 applicants for an interview?
Click here to see answer by jim_thompson5910(35256) |
Question 202533: Can someone please help me with these. A.S.A.P.
1) Indicate the formula for the following conditions.
P(X | Y) = ________
2) Type the general term for the following sequence.
3, 9, 27, 81, 243, . . . __________
3) Type the general term for the following sequence.
3/4, 6/5, 9/6, 12/7, 15/8 ...
4) Evaluate the following expression.
Pc(5,5) = ______
5) A person is wearing a bracelet with 11 settings around the bracelet. How many different ways can 11 birthstones be arranged around the bracelet? Leave the answer in factorial form. ________
6) How many different ways can an executive committee of nine people sit at a round table? _________
7) A compound experiment consists of drawing at random twice without replacing from a jar with 3 red, 3 white, and 2 black marbles. What is the probability of getting first a red and then a black marble? ________
Thank You,
~Sarah :)
Click here to see answer by rfer(16322) |
Question 203403: How many different ways can a committee of 9 be selected from a larger organization of 20 people?
I am sure this is a combination problem.
Which is 9C20=(just Guessing) 20! 20!
______ = ________
9!(20-9) 9!11!
20! 20*19*18*17*16*15*14*13*12*11*10*9*8*7*6*5*4*3*2*1
______________________________________________________
9!
i guess im confused. big numbers.
Click here to see answer by scott8148(6628)  |
Question 204192: If there are 2 apples and every year the percentage of apples increase by 2%. How many apples are there in 6000 years?
For the first year the formula seems to work 2+1[2(.02)]=2.04
For the second year, I think it should be 2.04+1[2.04(.02)]=2.0808
because we have to take into consideration the initial increase and 2% of the initial increase for further increase.
For the third year, 2.0808+1[2.0808(.02)]=2.122416
And so on.
How do I go about calculating the problem without having to do it 6000 times?
Click here to see answer by scott8148(6628) |
Question 204192: If there are 2 apples and every year the percentage of apples increase by 2%. How many apples are there in 6000 years?
For the first year the formula seems to work 2+1[2(.02)]=2.04
For the second year, I think it should be 2.04+1[2.04(.02)]=2.0808
because we have to take into consideration the initial increase and 2% of the initial increase for further increase.
For the third year, 2.0808+1[2.0808(.02)]=2.122416
And so on.
How do I go about calculating the problem without having to do it 6000 times?
Click here to see answer by Earlsdon(6294) |
Question 204215: Here is the question:
In how many ways can John, Todd, Lisa, and Marie line up so that they alternate gender?
Here is the solution that I came up with
(Choices for gender)*(Number of ways to arrange the genders)
There two choices for gender: either a girl or a boy.
For the first position you can choose two boys, in the second you can choose two girls, in the third you can choose one boy, and in the fourth you can choose one girl:
Here it is:
2 * 2*1*2*1 = 8 ways of arranging them so that the genders are always alternated.
Please let me know if my reasoning is correct.
Click here to see answer by solver91311(24713) |
Question 206869: For many years, the state of California used three letters followed by three digits on its automobile plates.
a) how many different license plates are possible w/ this arrangement?
b) when the state ran out of plates, the order was reversed to three digits followed by three letters. How many additional plates were then possible?
Click here to see answer by Edwin McCravy(20054)  |
Question 207307: I am trying to see if I figured this out correctly or not, the question is this: three men and three women line up at the check out counter, how many different ways can they line up. I got 22 different ways but want to check my answer, THANKS
Click here to see answer by Edwin McCravy(20054) |
Question 208487: A band’s new album contains 12 songs. The record company decides to promote
the album at a music festival by giving away CD samplers that contain 3 songs
from the album.
a. Does this situation involve combinations or permutations? Explain.
b. How many different ways can the band select songs for the sampler?
Click here to see answer by MRperkins(300)  |
Question 208485: A coach decides to choose 3 out of 5 athletes to compete in a race. How many different ways can the coach choose the athletes? Identify if the situation involves combination or permutations.
A 20; permutations
B 20; combinations
C 10; combinations
D 10; permutations
Click here to see answer by Theo(13342)  |
Question 212196: A number of small towns set up their own telephone system. Between each pair of towns they stretched a main phone cable. In all, they put up 28 separate cables connecting all of the towns. How many towns were there?
Click here to see answer by rapaljer(4671)  |
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Older solutions: 1..45, 46..90, 91..135, 136..180, 181..225, 226..270, 271..315, 316..360, 361..405, 406..450, 451..495, 496..540, 541..585, 586..630, 631..675, 676..720, 721..765, 766..810, 811..855, 856..900, 901..945, 946..990, 991..1035, 1036..1080, 1081..1125, 1126..1170, 1171..1215, 1216..1260, 1261..1305, 1306..1350, 1351..1395, 1396..1440, 1441..1485, 1486..1530, 1531..1575, 1576..1620, 1621..1665, 1666..1710, 1711..1755, 1756..1800, 1801..1845, 1846..1890, 1891..1935, 1936..1980, 1981..2025, 2026..2070, 2071..2115, 2116..2160, 2161..2205, 2206..2250, 2251..2295, 2296..2340, 2341..2385, 2386..2430, 2431..2475, 2476..2520, 2521..2565, 2566..2610, 2611..2655, 2656..2700, 2701..2745, 2746..2790, 2791..2835, 2836..2880, 2881..2925, 2926..2970, 2971..3015, 3016..3060, 3061..3105, 3106..3150, 3151..3195, 3196..3240, 3241..3285, 3286..3330, 3331..3375, 3376..3420, 3421..3465, 3466..3510, 3511..3555, 3556..3600, 3601..3645, 3646..3690, 3691..3735, 3736..3780, 3781..3825, 3826..3870, 3871..3915, 3916..3960, 3961..4005, 4006..4050, 4051..4095, 4096..4140, 4141..4185, 4186..4230, 4231..4275, 4276..4320, 4321..4365, 4366..4410, 4411..4455, 4456..4500, 4501..4545, 4546..4590, 4591..4635, 4636..4680, 4681..4725, 4726..4770, 4771..4815, 4816..4860, 4861..4905, 4906..4950, 4951..4995, 4996..5040, 5041..5085, 5086..5130, 5131..5175, 5176..5220, 5221..5265, 5266..5310, 5311..5355, 5356..5400, 5401..5445, 5446..5490, 5491..5535, 5536..5580, 5581..5625, 5626..5670, 5671..5715, 5716..5760, 5761..5805, 5806..5850, 5851..5895, 5896..5940, 5941..5985, 5986..6030, 6031..6075, 6076..6120, 6121..6165, 6166..6210, 6211..6255, 6256..6300, 6301..6345, 6346..6390, 6391..6435, 6436..6480, 6481..6525, 6526..6570, 6571..6615, 6616..6660, 6661..6705, 6706..6750, 6751..6795, 6796..6840, 6841..6885, 6886..6930, 6931..6975, 6976..7020, 7021..7065, 7066..7110, 7111..7155, 7156..7200, 7201..7245, 7246..7290, 7291..7335, 7336..7380, 7381..7425, 7426..7470, 7471..7515, 7516..7560, 7561..7605, 7606..7650, 7651..7695, 7696..7740, 7741..7785, 7786..7830, 7831..7875, 7876..7920, 7921..7965, 7966..8010, 8011..8055, 8056..8100, 8101..8145, 8146..8190, 8191..8235, 8236..8280, 8281..8325, 8326..8370, 8371..8415, 8416..8460, 8461..8505, 8506..8550, 8551..8595, 8596..8640, 8641..8685, 8686..8730, 8731..8775, 8776..8820, 8821..8865, 8866..8910, 8911..8955, 8956..9000, 9001..9045, 9046..9090, 9091..9135, 9136..9180, 9181..9225, 9226..9270, 9271..9315, 9316..9360, 9361..9405, 9406..9450, 9451..9495, 9496..9540, 9541..9585, 9586..9630, 9631..9675, 9676..9720, 9721..9765, 9766..9810, 9811..9855, 9856..9900, 9901..9945, 9946..9990, 9991..10035
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