Tutors Answer Your Questions about Permutations (FREE)
Question 926313: A club has 50 members.
a) How many ways are there to choose four members of the club to serve on an executive committee?
[Num] ways
b) How many ways are there to choose a president, vice president, secretary, and treasurer of the club, where no person can hold more than one office?
Click here to see answer by ewatrrr(24785)  |
Question 926588: In a cinema there are 10 rows with each row having 25 seats. The seats are numbered. If two friends buy tickets for themselves without knowing each other, what is the probability that they'll sit next to each other?
Click here to see answer by josmiceli(19441)  |
Question 926629: A coin is tossed with possible outcomes H or T. Then a spinner spun with possible outcomes 1 through 4; draw a tree diagram and list the combined outcomes. What is the probability of rolling an odd number and a tail?
Click here to see answer by stanbon(75887) |
Question 927161: In a group of 14 students, there are 8 girls and 6 boys.
a) Determine the number of ways that a committee of 4 students can be chosen from this group.
b) Determine the number of ways that a committee of 4 students which has exactly 2 girls can be chosen from the group.
c) Determine the number of ways that a committee of 4 students which has at least 1 boy can be chosen from the group.
d) The committee of 4 students must have 1 girl, 1 boy , and 2 other students, how many different committees can be chosen from this group?
I have solved a), b) and c) for the question, but I am not sure about d).
I thought maybe it could be worked out like this:
8C1 x 6C1 x 12C2 = 3,168
I don't know if that is right though. Any help would be greatly appreciated. Thank you!
Click here to see answer by ewatrrr(24785)  |
Question 927161: In a group of 14 students, there are 8 girls and 6 boys.
a) Determine the number of ways that a committee of 4 students can be chosen from this group.
b) Determine the number of ways that a committee of 4 students which has exactly 2 girls can be chosen from the group.
c) Determine the number of ways that a committee of 4 students which has at least 1 boy can be chosen from the group.
d) The committee of 4 students must have 1 girl, 1 boy , and 2 other students, how many different committees can be chosen from this group?
I have solved a), b) and c) for the question, but I am not sure about d).
I thought maybe it could be worked out like this:
8C1 x 6C1 x 12C2 = 3,168
I don't know if that is right though. Any help would be greatly appreciated. Thank you!
Click here to see answer by stanbon(75887) |
Question 927431: Which term in the expansion of (1/(2x^3) - x^5))^8 is a constant?
I know you expand it into the equation
= (nCk) a^(n-k) b^k
to get = 8Ck (1/(2x^3))^(8-k) (-x^5)^k
but I am not sure what to do after that.
Thank you for the help!
Click here to see answer by richard1234(7193)  |
Question 927615: 5 letters from the word "DRILLING" are arranged in a row.
I.Find the number of way in which this can be done, when the first letter is "I" and the last letter is "L".
a.If no letter maybe repeated.
b.If each letter occurs as many time as it does in DRILLING
Click here to see answer by Edwin McCravy(20054)  |
Question 927446: Three ladies have each brought a child for admission. The head of the school wishes to interview the six people in such a manner that no child is interviewed before his/her mother. What are the no. of ways of doing this?
Click here to see answer by richard1234(7193)  |
Question 927516: Eight plates are stacked in three piles with two piles of three plates each and one pile of
two plates. You are to pick up the plates one at a time following these rules:
1) You first choose a pile from which to pick up a plate.
2) You must then pick up the top plate from that pile.
By following these rules, in how many different orders can you pick up the eight plates?
Click here to see answer by Edwin McCravy(20054)  |
Question 927204: A van has 3 bench seats holding 3 people per bench. 9 passengers are going to get in the van: a couple, 3 family members, and 4 random people. The 3 family members will only go if they sit together on one bench and the couple will only go if they sit side by side. How many ways are there to arrange these passengers?
My answer: 5,120
Click here to see answer by Edwin McCravy(20054)  |
Question 927667: a) In how many ways can a committee consisting of three men and two women be chosen from seven men and five women?
b) How many committee of five with a given chairman can be selected from twelve persons?
c) In how many ways can a teacher choose one or more students from six eligible students?
d) Find the number of permutations that can be formed from the letters UNUSUAL?
Click here to see answer by Edwin McCravy(20054)  |
|
Older solutions: 1..45, 46..90, 91..135, 136..180, 181..225, 226..270, 271..315, 316..360, 361..405, 406..450, 451..495, 496..540, 541..585, 586..630, 631..675, 676..720, 721..765, 766..810, 811..855, 856..900, 901..945, 946..990, 991..1035, 1036..1080, 1081..1125, 1126..1170, 1171..1215, 1216..1260, 1261..1305, 1306..1350, 1351..1395, 1396..1440, 1441..1485, 1486..1530, 1531..1575, 1576..1620, 1621..1665, 1666..1710, 1711..1755, 1756..1800, 1801..1845, 1846..1890, 1891..1935, 1936..1980, 1981..2025, 2026..2070, 2071..2115, 2116..2160, 2161..2205, 2206..2250, 2251..2295, 2296..2340, 2341..2385, 2386..2430, 2431..2475, 2476..2520, 2521..2565, 2566..2610, 2611..2655, 2656..2700, 2701..2745, 2746..2790, 2791..2835, 2836..2880, 2881..2925, 2926..2970, 2971..3015, 3016..3060, 3061..3105, 3106..3150, 3151..3195, 3196..3240, 3241..3285, 3286..3330, 3331..3375, 3376..3420, 3421..3465, 3466..3510, 3511..3555, 3556..3600, 3601..3645, 3646..3690, 3691..3735, 3736..3780, 3781..3825, 3826..3870, 3871..3915, 3916..3960, 3961..4005, 4006..4050, 4051..4095, 4096..4140, 4141..4185, 4186..4230, 4231..4275, 4276..4320, 4321..4365, 4366..4410, 4411..4455, 4456..4500, 4501..4545, 4546..4590, 4591..4635, 4636..4680, 4681..4725, 4726..4770, 4771..4815, 4816..4860, 4861..4905, 4906..4950, 4951..4995, 4996..5040, 5041..5085, 5086..5130, 5131..5175, 5176..5220, 5221..5265, 5266..5310, 5311..5355, 5356..5400, 5401..5445, 5446..5490, 5491..5535, 5536..5580, 5581..5625, 5626..5670, 5671..5715, 5716..5760, 5761..5805, 5806..5850, 5851..5895, 5896..5940, 5941..5985, 5986..6030, 6031..6075, 6076..6120, 6121..6165, 6166..6210, 6211..6255, 6256..6300, 6301..6345, 6346..6390, 6391..6435, 6436..6480, 6481..6525, 6526..6570, 6571..6615, 6616..6660, 6661..6705, 6706..6750, 6751..6795, 6796..6840, 6841..6885, 6886..6930, 6931..6975, 6976..7020, 7021..7065, 7066..7110, 7111..7155, 7156..7200, 7201..7245, 7246..7290, 7291..7335, 7336..7380, 7381..7425, 7426..7470, 7471..7515, 7516..7560, 7561..7605, 7606..7650, 7651..7695, 7696..7740, 7741..7785, 7786..7830, 7831..7875, 7876..7920, 7921..7965, 7966..8010, 8011..8055, 8056..8100, 8101..8145, 8146..8190, 8191..8235, 8236..8280, 8281..8325, 8326..8370, 8371..8415, 8416..8460, 8461..8505, 8506..8550, 8551..8595, 8596..8640, 8641..8685, 8686..8730, 8731..8775, 8776..8820, 8821..8865, 8866..8910, 8911..8955, 8956..9000, 9001..9045, 9046..9090, 9091..9135, 9136..9180, 9181..9225, 9226..9270, 9271..9315, 9316..9360, 9361..9405, 9406..9450, 9451..9495, 9496..9540, 9541..9585, 9586..9630, 9631..9675, 9676..9720, 9721..9765, 9766..9810, 9811..9855, 9856..9900, 9901..9945, 9946..9990, 9991..10035
|