Tutors Answer Your Questions about Permutations (FREE)
Question 911620: On an assignment, students are expected to answer at least 3 questions from a 24 question set. But they can complete as many questions as they wish (for bonus!).
How many possible ways can they complete the assignment?
Click here to see answer by ewatrrr(24785)   |
Question 911604: Question: On an assignment, students are expected to answer at least 3 questions from a 19 question set. But they can complete as many questions as they wish (for bonus!).
How many possible ways can they complete the assignment?
Note: Consider all questions do-able, and each student will complete at least the minimum number of questions.
Can't seem to figure this problem out?! Help.
Click here to see answer by ewatrrr(24785) |
Question 912625: There are five people in my family. How many different groupings of these five people can be formed (i.e. groups with from 1 to 5 members)?
I know the answer is 31, but is there a formula for solving this? (Not homework, just a problem I thought of, and can't find a method on the internet!)
Thank you!
Click here to see answer by ichigo449(30) |
Question 912933: Suppose repetitions are not allowed. Answer the following:
a) Find how many three-digit numbers can be formed from the following six digits: 2, 3, 5, 6, 7, 9
b) How many even three-digit numbers can be formed from these six digits?
c) What is the probability that a three-digit number greater than 400 will be formed from these six
digits?
i am having problems especially with b, because there are only 2 even numbers.
Click here to see answer by ewatrrr(24785) |
Question 912953: One in a thousand people is a carrier of a particular heart disease. There is a test to detect this disease.
The test is 100% accurate for people who have the disease, and is 95% accurate for those who don't
(this means that 5% of people who do not have the disease will be wrongly diagnosed as having it). If a
randomly selected person tests positive, what is the probability that the person actually has the disease?
i just need help with the parameters, in the question imagine
A= has the disease
B =test result positive.
so will
A be 1/1000 , A' = 999/1000 ?
and i dont know what B will be, please help
Click here to see answer by ewatrrr(24785) |
Question 912978: A restaurant menu has 7 choices for a beverage, 15 choices for the main dish, 9 side dishes, and 5 choices for a dessert. You can choose one beverage, one main dish, one side dish, and one dessert. How many different meals are possible?
Click here to see answer by ewatrrr(24785) |
Question 912995: The percentage of Americans who are vegetarians is 3.2%. Four people are randomly selected and are asked if they are vegetarians. Find the probability that exactly one person said he or she is a vegetarian.
Click here to see answer by ewatrrr(24785) |
Question 913000: The percentage of Americans who are vegetarians is 3.2%. Four people are randomly selected and are asked if they are vegetarians. Find the probability that at most one person said they are vegetarians. Hint: You must find the probability that zero people (x = 0) and one person (x = 1) said they are vegetarians.
Click here to see answer by ewatrrr(24785) |
Question 913724: I want to find all the ways to order 5 people (numbered 1:5) in 3 rows (rows a:c).
the only constraint is that each row can contain only 3 people.
What i am looking for is the formula to do this.
Any help would be appreciated
thanks
Click here to see answer by rothauserc(4718)  |
Question 913724: I want to find all the ways to order 5 people (numbered 1:5) in 3 rows (rows a:c).
the only constraint is that each row can contain only 3 people.
What i am looking for is the formula to do this.
Any help would be appreciated
thanks
Click here to see answer by josmiceli(19441)  |
Question 915421: Hi, I'm having trouble with the following problem:
There are 7 boys and 5 girls in the debate squad at Franklin High School. In how many ways can a 4-member debating team be selected:
a. If there are no restrictions? (I found this one: C(12,4) = 495)
b. If 2 boys and 2 girls must be on the team? (I found this one too: C(7,2) x C(5,2) = 210
c. If at least two boys must be on the team? (I can't figure out how to set this one up.)
Help!! For C., I have tried multiple ways of working out the problem, but I need help with how to set it up. I know for C. is 420.
Thank you!
Click here to see answer by ewatrrr(24785) |
Question 915425: Hi, I'm really stuck on this card problem:
From a standard 52-card deck, how many 5-card poker hands can be dealt consisting of 3 kings and 1 pair?
Help! I can't figure out how to set this up at all. I know the answer is 288.
Thank you!
Click here to see answer by ewatrrr(24785) |
Question 916586: I have tried solving this type of question multiple times, I am not sure if I am missing a step somewhere. The question is:
A insurance fraud inspector is going to audit 7 people from a pool of 18 people. How many different combinations are there?
I'm pretty sure you would use the formula 18!/ 7!(18-7)! however, my calculator does not have n! or any others to work these formulas so I am having to plug everything in on my own in my calculator. Have read thoroughly through my book and professor provided no lecture for this unit. In desperate need of explaining. I know that when the order doesn't matter, but you don't have the same total you would do 18*17*16....etc. Not sure what I'm doing wrong.
Click here to see answer by ewatrrr(24785) |
|
Older solutions: 1..45, 46..90, 91..135, 136..180, 181..225, 226..270, 271..315, 316..360, 361..405, 406..450, 451..495, 496..540, 541..585, 586..630, 631..675, 676..720, 721..765, 766..810, 811..855, 856..900, 901..945, 946..990, 991..1035, 1036..1080, 1081..1125, 1126..1170, 1171..1215, 1216..1260, 1261..1305, 1306..1350, 1351..1395, 1396..1440, 1441..1485, 1486..1530, 1531..1575, 1576..1620, 1621..1665, 1666..1710, 1711..1755, 1756..1800, 1801..1845, 1846..1890, 1891..1935, 1936..1980, 1981..2025, 2026..2070, 2071..2115, 2116..2160, 2161..2205, 2206..2250, 2251..2295, 2296..2340, 2341..2385, 2386..2430, 2431..2475, 2476..2520, 2521..2565, 2566..2610, 2611..2655, 2656..2700, 2701..2745, 2746..2790, 2791..2835, 2836..2880, 2881..2925, 2926..2970, 2971..3015, 3016..3060, 3061..3105, 3106..3150, 3151..3195, 3196..3240, 3241..3285, 3286..3330, 3331..3375, 3376..3420, 3421..3465, 3466..3510, 3511..3555, 3556..3600, 3601..3645, 3646..3690, 3691..3735, 3736..3780, 3781..3825, 3826..3870, 3871..3915, 3916..3960, 3961..4005, 4006..4050, 4051..4095, 4096..4140, 4141..4185, 4186..4230, 4231..4275, 4276..4320, 4321..4365, 4366..4410, 4411..4455, 4456..4500, 4501..4545, 4546..4590, 4591..4635, 4636..4680, 4681..4725, 4726..4770, 4771..4815, 4816..4860, 4861..4905, 4906..4950, 4951..4995, 4996..5040, 5041..5085, 5086..5130, 5131..5175, 5176..5220, 5221..5265, 5266..5310, 5311..5355, 5356..5400, 5401..5445, 5446..5490, 5491..5535, 5536..5580, 5581..5625, 5626..5670, 5671..5715, 5716..5760, 5761..5805, 5806..5850, 5851..5895, 5896..5940, 5941..5985, 5986..6030, 6031..6075, 6076..6120, 6121..6165, 6166..6210, 6211..6255, 6256..6300, 6301..6345, 6346..6390, 6391..6435, 6436..6480, 6481..6525, 6526..6570, 6571..6615, 6616..6660, 6661..6705, 6706..6750, 6751..6795, 6796..6840, 6841..6885, 6886..6930, 6931..6975, 6976..7020, 7021..7065, 7066..7110, 7111..7155, 7156..7200, 7201..7245, 7246..7290, 7291..7335, 7336..7380, 7381..7425, 7426..7470, 7471..7515, 7516..7560, 7561..7605, 7606..7650, 7651..7695, 7696..7740, 7741..7785, 7786..7830, 7831..7875, 7876..7920, 7921..7965, 7966..8010, 8011..8055, 8056..8100, 8101..8145, 8146..8190, 8191..8235, 8236..8280, 8281..8325, 8326..8370, 8371..8415, 8416..8460, 8461..8505, 8506..8550, 8551..8595, 8596..8640, 8641..8685, 8686..8730, 8731..8775, 8776..8820, 8821..8865, 8866..8910, 8911..8955, 8956..9000, 9001..9045, 9046..9090, 9091..9135, 9136..9180, 9181..9225, 9226..9270, 9271..9315, 9316..9360, 9361..9405, 9406..9450, 9451..9495, 9496..9540, 9541..9585, 9586..9630, 9631..9675, 9676..9720, 9721..9765, 9766..9810, 9811..9855, 9856..9900, 9901..9945, 9946..9990, 9991..10035
|
