Tutors Answer Your Questions about Permutations (FREE)
Question 885178: There are 6 members of a club; 4 women and 2 men.
(A) in how many ways canthey line up for a picture?
(B) in how many ways can they select a man and a woman to attend a meeting?
(C) if 1 of the men is absent from their meeting, in how many ways could a man open the meeting and a woman close the meeting?
Please help!
Click here to see answer by Edwin McCravy(20054)  |
Question 890639: how many 3 digit numbers can be formed using 0,1,2, and 3 if no 2 digits are the same?
the solution used was H T U = 3 x 3 x 2 = 18
i didn't get how hundreds, tens, and unit became 3 x 3 x 2. is there a way for me to easily understand?
thanks in advance.
Click here to see answer by KMST(5328)  |
Question 890882: How many different tips could you leave in a restaurant if you had a quarter, a half-dollar, a dollar, 5-dollar bill, and a 10 dollar bill?
I think the answer is 32 ways, since there are 5 different payment choices, and you can either leave the tip, or not leave the tip, which makes it 2 for choosing either to leave or not, so then the answer is 2 to the power of 5, which is 2^5 = 32. Am I correct?
Thank You!
Click here to see answer by richwmiller(17219)  |
Question 890985: A binary number consists only 0s and 1s.
A) How may different seven-digit binary numbers are there?
B) How may different seven-digit binary numbers are there which begin with a 1 and which contain exactly four 1s.
C) How may different seven-digit binary numbers are there which contain exactly four 1s which are all adjacent(next to each other)?
Click here to see answer by Edwin McCravy(20054)  |
Question 890984: Consider strings of length 6 which contain letters only from the set { P,Q,R,S,T} and digits from { 1,3,5,7,9}. for example TPR5Q7 is such a string.Suppose repetition allowed.
A) How many different strings are there?
B) How may of these strings have no P?
C) How may of these strings have at least one P?
D) How may of these strings have exactly two P's and one 7?
Click here to see answer by Edwin McCravy(20054)  |
Question 890885: A United States Delegation consists of 6 Americans, 5 Russians, and 4 Chinese. How many committees of three people have more Americans than Russians?
AND
How many committees of three people do not have all three Americans?
Thank You!
Click here to see answer by Edwin McCravy(20054)  |
Question 890824: The following problems deal with permutations of the eight letters A, B, C, D, E, F, G and H.
a. What is the number of 8-permutations if A and B have to be among the first three letters?
b. What is the number of 6-permutations if ‘FG’ should not be at the end?
c. What is the number of 5-permutations containing A, B and C but not adjacent to one another?
Click here to see answer by Edwin McCravy(20054)  |
Question 891173: 12. There are 20 quarts of milk on a supermarket shelf, four of which are spoiled. A customer buys three quarts of milk.
(a) How many samples are possible?
(b) How many samples contain exactly two quarts of spoiled milk?
(c) How many samples contain at least two quarts of spoiled milk?
Click here to see answer by Theo(13342)  |
Question 891344: Five dogs (Fido, Ruff, Lassie, Odie, and Snoopy) were playing in the park. Altogether, they had 5 identical Frisbees. In how many ways could the 5 Frisbees be distributed among the dogs when they leave the park to go home?
Click here to see answer by richard1234(7193)  |
Question 891399: if 2 students move from van a to b the two van will have the same number of students but if two students move from van b to a van b will have half the number of students that were in a. Show at least one equation to get a mark.
Click here to see answer by JulietG(1812)  |
Question 891210: How many four-digit even numbers can be formed from the digits 0,2,3,5,6, and 9 if all for digits are different? The given answer is 108, but when i tried it out i got stuck because of the extra number and got 120 .....
Click here to see answer by AnlytcPhil(1806)  |
Question 891439: a child is asked to reach inside a bag to randomly select a piece of candy from 25 chocolates, 15 caramels, and 10 peppermints. Find the probability:
A) A caramel
B) A Peppermint
c) either a chocolate or a caramel.
Click here to see answer by Fombitz(32388)  |
Question 891547: Ralph knows that there are 15 distinguishable possibilities when 2 people are chosen to form a committee from a particular group of N people.
A) describe what values if N would be admissible in this problem
B) Determine the number of people in the larger group, N
Click here to see answer by Edwin McCravy(20054)  |
Question 887263: Hi I really need help with these questions please. Im not good at questions pertaining cards.
1) From a standard deck of 52 cards (no jokers)
a) In how many ways could you choose a red five or a club?
b) In how many ways could you choose a jack or a red card?
Click here to see answer by Edwin McCravy(20054)  |
Question 891977: consider strings of length 10 which contain only letters from the set{A,E,I,O,U} and digits from {1,3,5,7,9}suppose repetition of letters is not allowed.
a) how many different strings are there?
b) How many different strings are there if the letters,i.e A,E,I,O,U and the digits,i.e 1,3,5,7,9 must alternate?
c) How many different strings are there if all five letters must be adjacent in each string?
Click here to see answer by Edwin McCravy(20054)  |
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Older solutions: 1..45, 46..90, 91..135, 136..180, 181..225, 226..270, 271..315, 316..360, 361..405, 406..450, 451..495, 496..540, 541..585, 586..630, 631..675, 676..720, 721..765, 766..810, 811..855, 856..900, 901..945, 946..990, 991..1035, 1036..1080, 1081..1125, 1126..1170, 1171..1215, 1216..1260, 1261..1305, 1306..1350, 1351..1395, 1396..1440, 1441..1485, 1486..1530, 1531..1575, 1576..1620, 1621..1665, 1666..1710, 1711..1755, 1756..1800, 1801..1845, 1846..1890, 1891..1935, 1936..1980, 1981..2025, 2026..2070, 2071..2115, 2116..2160, 2161..2205, 2206..2250, 2251..2295, 2296..2340, 2341..2385, 2386..2430, 2431..2475, 2476..2520, 2521..2565, 2566..2610, 2611..2655, 2656..2700, 2701..2745, 2746..2790, 2791..2835, 2836..2880, 2881..2925, 2926..2970, 2971..3015, 3016..3060, 3061..3105, 3106..3150, 3151..3195, 3196..3240, 3241..3285, 3286..3330, 3331..3375, 3376..3420, 3421..3465, 3466..3510, 3511..3555, 3556..3600, 3601..3645, 3646..3690, 3691..3735, 3736..3780, 3781..3825, 3826..3870, 3871..3915, 3916..3960, 3961..4005, 4006..4050, 4051..4095, 4096..4140, 4141..4185, 4186..4230, 4231..4275, 4276..4320, 4321..4365, 4366..4410, 4411..4455, 4456..4500, 4501..4545, 4546..4590, 4591..4635, 4636..4680, 4681..4725, 4726..4770, 4771..4815, 4816..4860, 4861..4905, 4906..4950, 4951..4995, 4996..5040, 5041..5085, 5086..5130, 5131..5175, 5176..5220, 5221..5265, 5266..5310, 5311..5355, 5356..5400, 5401..5445, 5446..5490, 5491..5535, 5536..5580, 5581..5625, 5626..5670, 5671..5715, 5716..5760, 5761..5805, 5806..5850, 5851..5895, 5896..5940, 5941..5985, 5986..6030, 6031..6075, 6076..6120, 6121..6165, 6166..6210, 6211..6255, 6256..6300, 6301..6345, 6346..6390, 6391..6435, 6436..6480, 6481..6525, 6526..6570, 6571..6615, 6616..6660, 6661..6705, 6706..6750, 6751..6795, 6796..6840, 6841..6885, 6886..6930, 6931..6975, 6976..7020, 7021..7065, 7066..7110, 7111..7155, 7156..7200, 7201..7245, 7246..7290, 7291..7335, 7336..7380, 7381..7425, 7426..7470, 7471..7515, 7516..7560, 7561..7605, 7606..7650, 7651..7695, 7696..7740, 7741..7785, 7786..7830, 7831..7875, 7876..7920, 7921..7965, 7966..8010, 8011..8055, 8056..8100, 8101..8145, 8146..8190, 8191..8235, 8236..8280, 8281..8325, 8326..8370, 8371..8415, 8416..8460, 8461..8505, 8506..8550, 8551..8595, 8596..8640, 8641..8685, 8686..8730, 8731..8775, 8776..8820, 8821..8865, 8866..8910, 8911..8955, 8956..9000, 9001..9045, 9046..9090, 9091..9135, 9136..9180, 9181..9225, 9226..9270, 9271..9315, 9316..9360, 9361..9405, 9406..9450, 9451..9495, 9496..9540, 9541..9585, 9586..9630, 9631..9675, 9676..9720, 9721..9765, 9766..9810, 9811..9855, 9856..9900, 9901..9945, 9946..9990, 9991..10035
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