Tutors Answer Your Questions about Permutations (FREE)
Question 470672: 1) The freshman class has 300 students. Each freshman must write three reports from a list of 18 novels that the teacher has assigned them to read. How many different combinations of novels can a freshman student choose to write reports on?
54
816
4,896
2)How many possible three-digit passwords can be formed using digits 1 through 9 if no digits are repeated?
27
504
729
3)In how many different ways can you answer a multiple choice test that has four questions and five choices for each answer?
205
625
1024
Click here to see answer by ewatrrr(24785)  |
Question 471631: A) If a club has 13 members, how many ways can a board of 3 officials can be chosen with individual mittens?
B) If 2 cards are drawn from a 52 card deck without replacing it, what is the probability of drawing a Jack and a 10?
C) Given a box with 2 purple, 6 red, and 9 green, what is the probability of randomly drawing a match?
D) A friend gave you 100 lottery tickets for your birthday. The probability of winning a prize is .012. What is the probability that you will have at least 2 winning tickets?
Click here to see answer by edjones(8007)  |
Question 472664: Dear math teacher,
I really need help with the following word problem:
There are 4 hooks on a wall. In how many ways can 3 coats be hung on them, one coat on a hook?
I solved it several times and was kind of sure of an answer but my book says 24, and I got 12. Here is how I did it:
4 times Permutation of taking 3 coats and hanging them one at a time because we have 4 hooks. That gives me 12 ways. I also drew a picture of coat 1, coat 2, and coat 3, and started hanging each coat on hook 1, 2, 3, and 4 making a tree below each coat. Each tree gave me 4 ways to hand a coat on a hook, and for 3 coats, I simply added 4 + 4 + 4 ways = 12 ways. So, I got the same answer twice. But then, I did permutation of taking 4 hooks and hanging 3 coats on them and I got 16 ways but this does not make sense because units to the left of permutation must match the units to the right of permuation and I have 4 hooks to the left and 3 coats to the right, so I knew that's is the wrong approach. This kind of reassured me that the first two approaches are correct.
Please help me figure out this problem. I would really appreciate it. Thank you so much. And have a wonderful day.
Click here to see answer by edjones(8007)  |
Question 472794: An examination paper contains 12 different questions of which 3 are on trigonometry, 4 are on algebra and 5 on calculus. Girls are asked to answer 8 questions. Calculate:
i) the number of different ways in which a girl can select 8 questions if there is no restriction,
ii) the number of these selections which contain questions on only 2 of the 3 topics,trigonometry, algebra and calculus.
*Please answer as soon as possible bro :)
Click here to see answer by stanbon(75887) |
Question 472796: A fashion magazine runs a competition, in which 8 photographs of dresses are shown, lettered
A, B, C, D, E, F, G and H. Competitors are asked to submit an arrangement of 5 letters
showing their choice of dresses in descending order of merit. The winner is picked at random
from those competitors whose arrangement of letters agrees with that chosen by a panel of
experts.
(i) Calculate the number of possible arrangements of 5 letters chosen from the 8.
Calculate the number of these arrangements
(ii) in which A is placed first,
(iii) which contain A.
*Please answer as soon as possible bro :)
Click here to see answer by sudhanshu_kmr(1152)  |
Question 472891: This question has five answer choices. Select the best one of
the answer choices given.
16. The figure shows a normal distribution with mean m and
standard deviation d, including approximate percents of
the distribution in each of the six regions shown.
For a population of 800,000 subway riders, the numbers of
subway trips taken per rider last January are approximately
normally distributed with a mean of 56 trips and a standard
deviation of 13 trips. Approximately how many of the riders
took between 30 and 43 trips last January?
A 60,000
B 110,000
C 160,000
D 210,000
E 270,000
Drawing a picture of the the distribution table will solve this.
Click here to see answer by edjones(8007)  |
Question 472881: An artist is invited to exhibit 4 new paintings and 3 new sculptures at a gallery space. If the artist has 7 paintings and 5 sculptures from which he must pick the artworks he will exhibit, how many different possible combinations of paintings and sculptures does he have from which to choose?
Click here to see answer by edjones(8007)  |
Question 472998: One student representative is selected from each of four clubs. In how many different ways can four students be selected, given the following number of members. Rodeo Club, 40 members; Kite Club, 27 members; Frisbee Club, 85 members; and Conoeing club, 34 members.
Click here to see answer by sudhanshu_kmr(1152)  |
Question 473465: I need to know the formula to find the answer to the following questions:
In how many ways can 8 people sit around a round table? and using all the prime numbers less than 10 how many four-digit even numbers can be made if repetition is not allowed.
Click here to see answer by stanbon(75887) |
Question 473509: Dear math teacher,
I am having difficulites solving the following math problem:
In how many ways can 9 different prizes be awarded to two students so that one receives 3 and the other 6?
So far, I got two answers but they are incorrect. The correct answer is 168.
Here is what I did so far:
First, I said to myself, this might be done this way: Permutation = 9 factorial divided by (3 factorial times 6 factorial) and that equals to 84. However, that's not the right answer. So then, I calculated: Permutation of 9 things taken 3 at a time TIMES Permution of 6 things taken 6 at time = 82.080. However, it's not the right answer either.
Would you please help me solve this problem? Thank you so much.
Yours,
I.
Click here to see answer by stanbon(75887) |
Question 473509: Dear math teacher,
I am having difficulites solving the following math problem:
In how many ways can 9 different prizes be awarded to two students so that one receives 3 and the other 6?
So far, I got two answers but they are incorrect. The correct answer is 168.
Here is what I did so far:
First, I said to myself, this might be done this way: Permutation = 9 factorial divided by (3 factorial times 6 factorial) and that equals to 84. However, that's not the right answer. So then, I calculated: Permutation of 9 things taken 3 at a time TIMES Permution of 6 things taken 6 at time = 82.080. However, it's not the right answer either.
Would you please help me solve this problem? Thank you so much.
Yours,
I.
Click here to see answer by jim_thompson5910(35256) |
Question 473539: Dear math teacher,
Would you please help me solve this problem?
Find n if
3times {(2n+4)Permutation3} = 2times {(n+4)Permutation4}
Here is what I got:
3 times (2n+4) times (2n+3) times (2n+2) = 2 times (n+4) times (n+3) times (n+2) times (n+1)
But then I am not sure how to isolate n on one side of the equation to solve for it. The correct answer is: 6.
Thank you very much for your time and effort in helping me with my homework.
I.
Click here to see answer by ccs2011(207)  |
Question 473682: This is a real life question, just curious how to figure it. I have a ceiling fan part with 4 connections (labeled L,1,2,and 3) and 4 different colors of wires (purple, black, yellow and grey.) How many possible combinations would I have if I didn't know what color of wire went into which connector?
Click here to see answer by Alan3354(69443)  |
Question 473441: Roberto's mom takes him to the toy store. There are 6 types of green balls, 8 types of blue balls and 5 types of red balls. If Roberto's mom allows him to get one of each color, how many options does Roberto have?
Click here to see answer by ewatrrr(24785)  |
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Older solutions: 1..45, 46..90, 91..135, 136..180, 181..225, 226..270, 271..315, 316..360, 361..405, 406..450, 451..495, 496..540, 541..585, 586..630, 631..675, 676..720, 721..765, 766..810, 811..855, 856..900, 901..945, 946..990, 991..1035, 1036..1080, 1081..1125, 1126..1170, 1171..1215, 1216..1260, 1261..1305, 1306..1350, 1351..1395, 1396..1440, 1441..1485, 1486..1530, 1531..1575, 1576..1620, 1621..1665, 1666..1710, 1711..1755, 1756..1800, 1801..1845, 1846..1890, 1891..1935, 1936..1980, 1981..2025, 2026..2070, 2071..2115, 2116..2160, 2161..2205, 2206..2250, 2251..2295, 2296..2340, 2341..2385, 2386..2430, 2431..2475, 2476..2520, 2521..2565, 2566..2610, 2611..2655, 2656..2700, 2701..2745, 2746..2790, 2791..2835, 2836..2880, 2881..2925, 2926..2970, 2971..3015, 3016..3060, 3061..3105, 3106..3150, 3151..3195, 3196..3240, 3241..3285, 3286..3330, 3331..3375, 3376..3420, 3421..3465, 3466..3510, 3511..3555, 3556..3600, 3601..3645, 3646..3690, 3691..3735, 3736..3780, 3781..3825, 3826..3870, 3871..3915, 3916..3960, 3961..4005, 4006..4050, 4051..4095, 4096..4140, 4141..4185, 4186..4230, 4231..4275, 4276..4320, 4321..4365, 4366..4410, 4411..4455, 4456..4500, 4501..4545, 4546..4590, 4591..4635, 4636..4680, 4681..4725, 4726..4770, 4771..4815, 4816..4860, 4861..4905, 4906..4950, 4951..4995, 4996..5040, 5041..5085, 5086..5130, 5131..5175, 5176..5220, 5221..5265, 5266..5310, 5311..5355, 5356..5400, 5401..5445, 5446..5490, 5491..5535, 5536..5580, 5581..5625, 5626..5670, 5671..5715, 5716..5760, 5761..5805, 5806..5850, 5851..5895, 5896..5940, 5941..5985, 5986..6030, 6031..6075, 6076..6120, 6121..6165, 6166..6210, 6211..6255, 6256..6300, 6301..6345, 6346..6390, 6391..6435, 6436..6480, 6481..6525, 6526..6570, 6571..6615, 6616..6660, 6661..6705, 6706..6750, 6751..6795, 6796..6840, 6841..6885, 6886..6930, 6931..6975, 6976..7020, 7021..7065, 7066..7110, 7111..7155, 7156..7200, 7201..7245, 7246..7290, 7291..7335, 7336..7380, 7381..7425, 7426..7470, 7471..7515, 7516..7560, 7561..7605, 7606..7650, 7651..7695, 7696..7740, 7741..7785, 7786..7830, 7831..7875, 7876..7920, 7921..7965, 7966..8010, 8011..8055, 8056..8100, 8101..8145, 8146..8190, 8191..8235, 8236..8280, 8281..8325, 8326..8370, 8371..8415, 8416..8460, 8461..8505, 8506..8550, 8551..8595, 8596..8640, 8641..8685, 8686..8730, 8731..8775, 8776..8820, 8821..8865, 8866..8910, 8911..8955, 8956..9000, 9001..9045, 9046..9090, 9091..9135, 9136..9180, 9181..9225, 9226..9270, 9271..9315, 9316..9360, 9361..9405, 9406..9450, 9451..9495, 9496..9540, 9541..9585, 9586..9630, 9631..9675, 9676..9720, 9721..9765, 9766..9810, 9811..9855, 9856..9900, 9901..9945, 9946..9990, 9991..10035
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